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Lyrx [107]
3 years ago
12

ITEM BANK: Move to Bottom 2a + b 2b + a 3(a + b) 4b-a 6a - 2b 1 drag and drop answer here 2 drag and drop answer here 3 drag and

droplanswerhere dragandid tegenovering 5 5 dieganddoplafsviete​
Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

ABC

Step-by-step explanation:

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p.s a calculator does exist.
7 0
3 years ago
Write an equation of a line containing (2, -3) and perpendicular to 3x+4y=14 answer
Sergio039 [100]

Answer:

Step-by-step explanation:

From the condition of perpendicularity, if two lines must be perpendicular to each other, the product of their gradient rather the slope must be equaled to ( -1 ).

Equation of a line ; y = mx+ c, where m1 is the gradient of the line and c us the point of intersection if the line on the y- axis.therefore, the equation

3x + 4y = 14, when re arranged, now becomes, 4y = -3x + 14, divide through by 4, gives, y = -3x/4 + 14.

Therefore, m1, = -3/4 and m2, = 4/3 going by the condition. Since the line passes through the coordinate of (2,3), where x = 2, and y = -3, then, substitute for x and y in y = mx+ c, minding the m2, to find C, therefore,

-3 = 4/3x2 + c. -3 = 8/3 +c

Multiply through by 3 to make it a linear equation,

-9 = 8 + 3c; -9 - 8 = 3c, -17= 3c

c = -17/3.Now substitute for c in the equation ,y = mx+ c, the equation now becomes, y = 4x/3 - 17/3. Therefore the new equation is

3y = -4x - 17.

7 0
3 years ago
I need some help........
Ad libitum [116K]

Answer:

Do you know any moderators I need one

Step-by-step explanation:

6 0
3 years ago
How do I graph y=5/3x
babymother [125]
Just do the slope of 5/3×

6 0
3 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
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