If;
A = Adjacent
O = Opposite
H = Hypotenuse
Then,
Sin Ф = O/H
Cos Ф = A/H
Therefore,
(Sin Ф)/Cos Ф) = (O/H)/(A/H) = (O/H)*(H/A) = O/A
Now,
tan Ф = O/A ----
Therefore, it is true that
tan Ф = SinФ/CosФ
Siny/2.7=sin63/2.8
siny=2.7sin63/2.8
y=arcsin((2.7sin63)/2.8)
y≈59.23° (to nearest one-hundredth of a degree)
Answer:
I do not know what math curriculum this is I'm sorry
9514 1404 393
Answer:
The given graph shows a function of x.
Step-by-step explanation:
Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.
The graph is a relation that is a function of x.
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The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.
Answer:
A%7.2= ( 7.5№) =(+--+) this is the best answer