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vovikov84 [41]
3 years ago
14

2 4 6 8 y 21 18 15 12 A. linear B. nonlinear​

Mathematics
2 answers:
dlinn [17]3 years ago
7 0

Answer:linear!

Step-by-step explanation:

Ivanshal [37]3 years ago
4 0

Answer:

linear!! (constant rate...)

Step-by-step explanation:

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Thesumoftwopositivenumbersis16.whatisthesmallest possible value of the sum of their squares?
anygoal [31]
X+y=16
the sum of the squares is
x^2+y^2=sum

solve for y in first equation
x+y=16
y=16-x
subsitiute that for y in other equation

x^2+(16-x)^2=sum
x^2+x^2-32x+256=sum
2x^2-32x+256=sum
take derivitive to find the minimum value (or just find the vertex because the parabola opens up)
derivitive is
4x-32=derivitve of sum
the max/min is where the derivitive equals 0
4x-32=0
4x=32
x=8

at x=8
so then y=16-8=8

the smallest value then is 8^2+8^2=64+64=128
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4 years ago
Express 2/3 in minutes
Yuliya22 [10]
To find 2/3 of an hour first we will divide 1 hour that is 60 mins into 3parts so we will get 20 mins.
5 0
3 years ago
Determine the truth value of each statement based on the expression. 6x^2 - 2x - 14y + 3x 1. There are 4 terms. (True or False)
Blababa [14]
1. True

2. False

3. False

4. False

5. True
8 0
3 years ago
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Each person in share's family of 5 eats 3 bowls of cereal each week. Her mother is going grocery shopping and wants to know how
Colt1911 [192]
Y = 5(3x)....y = total number of bowls and x = number of weeks

for 4 weeks......x = 4
y = 5(3*4)
y = 5(12)
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7 0
3 years ago
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A rectangle is fenced off for a robot competition. The dimensions of the competition area are 35 feet by 25 feet. To help track
xz_007 [3.2K]

Answer:

The approximate speed of the robot during the 5 seconds is:

  • <u>6 ft/s</u>

Step-by-step explanation:

To calculate the speed of the robot, you must begin with the positions, the first position (3, 18) and the second position (31, 6), you can see, in the height it moved from 3 to 31, it means 28 feet, in the width it moves from 18 to 6, it means 12 feet, with these data you can construct a triangle where you have the opposite leg and adjacent leg, now you must calculate the hypotenuse, because it is the linear path from the first position to the second position that the robot took, for this, you can use the Pythagoras theorem:

  • hypotenuse^{2} = opposite leg^{2} + adjacent leg^{2}
  • hypotenuse^{2} = 12^{2} +28^{2}
  • hypotenuse=\sqrt{ 12^{2}+28^{2}  }
  • hypotenuse=30.46 ft

With the value of the distance traveled, and the time used (5 seconds), we can calculate the speed with the next formula:

  • Speed =\frac{distance}{time}
  • Speed = \frac{30.46 ft}{5 s}
  • Speed = 6.09 ft/s

As you need the speed in the nearest whole number, then:

  • <u>Speed = 6 ft/s</u>
5 0
3 years ago
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