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kaheart [24]
3 years ago
14

If a third plane could be drawn which contains both lines a and b .

Mathematics
1 answer:
allsm [11]3 years ago
6 0

Answer:

must be parallel

Step-by-step explanation:

They must be parallel.

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Point p was rotated about the origin (0,0) by -15 degrees.<br><br> Which point is the image of P?
Airida [17]

Answer:

the answer is d.

Step-by-step explanation:

8 0
3 years ago
Jackson bought 555 ounces of raisins for \$4$4dollar sign, 4.
Fynjy0 [20]

Answer:

Part a) The raisins cost $0.8 per ounce

Part b) 1.25 ounces

Step-by-step explanation:

<u><em>The correct question is</em></u>

Jackson bought 5 ounces of raisins for $4 dollars.

a) How much do raisins cost per ounce?

b) How many ounces of raisins can be bought for $1?

Part a)  How much do raisins cost per ounce?

we know that

To find out the unit rate divide the total cost by the total weight

so

\frac{4}{5} =\$0.8\ per\ ounce

therefore

The raisins cost $0.8 per ounce

Part b) How many ounces of raisins can be bought for $1?

we know that

The raisins cost $0.8 per ounce

using proportion

Find out how many ounces of raisins can be bought for $1

Let

x -----> the ounces of raisins

\frac{1}{0.8}=\frac{x}{1}\\\\x= 1.25\ ounces

8 0
3 years ago
Read 2 more answers
Patty is ordering vests for her scout troop to wear in the Veterans Day parade. She ordered 12 vests from the Festive Features c
anygoal [31]

Answer:

Step-by-step explanation:

7 0
3 years ago
A student has a 30% chance of receiving chocolate ice cream for dessert at lunch. A statistics class designs a simulation to app
Nadusha1986 [10]

The count of the sections the class should label as "Chocolate Ice Cream" is 3.

<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

For the considered case, it is given that:

Probability of an student getting Chocolate Ice Cream for dessert at lunch =  30% = 0.3

The count of the sections the class should label as "Chocolate Ice Cream" should be such that spinner getting "Chocolate Ice Cream" as option should have the probability as 0.3

Let the count of the sections the class should label as "Chocolate Ice Cream"  be x

Then, as there are in total 10 sections in the spinner, and all sections are assumingly equally probable, thus, if the event E is:

E = event of getting "Chocolate Ice Cream" in the spinner ,

then as n(E) = x (as there are x sections with label "Chocolate Ice Cream")

and n(S) = total count of sections (size of sample space)  = 10

Thus, we get probability of event E as:

P(E) = \dfrac{n(E)}{n(S)} = \dfrac{x}{10}

This needs to be equal to 0.3, thus,

0.3 = \dfrac{x}{10}\\x = 3


Thus, the count of the sections the class should label as "Chocolate Ice Cream" is 3.

Learn more about probability here:

brainly.com/question/1210781

3 0
2 years ago
Read 2 more answers
Which graph shows data that would allow the most accurate prediction for the number of water bottles a vendor sells based on the
Mashcka [7]
It is either C or D because as temperatures rise the sells would increase.
6 0
3 years ago
Read 2 more answers
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