It was would numbers 000-000-0000 through 999-999-9999. So that would be 9,999,999,999 + 1 = 10 billion different 10-digit phone numbers.
Answer:
-33.5
Step-by-step explanation:
So this is a dot products vector problem, so the i and j represent x and y or horizontal and vertical components. So you multiple 3i and -0.5i and then separately multiply 8j and -4j. You get -1.5 and -32. Now all you have to do is add them and you get -33.5.
Basically in short:
1. Multiply the “i’s”.
2. Multiply the “j’s”.
3. Add the two products together.
HOPE THIS HELPS !! :-)
2x +4y =10x-3y =12
2x +4y =12 -----eq. 1
10x-3y =12 -------eq.2
2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y
Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23
Now, substitute this value of y in any equations given above
10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230
