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djyliett [7]
2 years ago
11

Find the quotient. 5^-3/5^-1

Mathematics
1 answer:
Ivan2 years ago
5 0

Answer:

3/35

Step-by-step explanation:

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Math question picture included<br><br>A.40m<br>B. 36m<br>C. 32 m<br>D. 30 m
Katarina [22]

Answer: 32 meters

Explanation: The 4 meter pole casts a shadow of 5 meters. The towers unknown height casts a shadow of 40 meters. Now isolate the shadows. 5 and 40. 40 divided by 5 is 8, so 4 times 8 is 32.




6 0
3 years ago
The length of a rectangle is twice the with. If the perimeter of the rectangle is 60 units, find the area of the garden
Darya [45]

w - width

2w - length

60 - perimeter

w + w + 2w + 2w = 6w - perimeter

The equation:

6w = 60    <em>divide both sides by 6</em>

w = 10 → 2w = 2 · 10 = 20

The area: A = width × length

A = (10)(20) = 200

<h3>Answer: The area of the garden is equal 200 square units.</h3>
4 0
2 years ago
5x + 4y = 11<br> 2x + 6y = -7
olga55 [171]

\left\{\begin{array}{ccc}5x+4y=11&|\cdot2\\2x+6y=-7&|\cdot(-5)\end{array}\right\\\underline{+\left\{\begin{array}{ccc}10x+8y=22\\-10x-30y=35\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ \ \ \ \ \ \ -22y=57\ \ \ \ |:(-22)\\.\ \ \ \ \ \ \ \ \ \ \ y=-\dfrac{57}{22}\\\\substitute\ the\ value\ of\ y\ to\ the\ first\ equation\\\\5x+4\left(-\dfrac{57}{22}\right)=11\\\\5x-2\cdot\dfrac{57}{11}=11\ \ \ \ |\cdot11\\\\55x-114=121\ \ \ \ |+114\\\\55x=135\ \ \ \ |:55

x=\dfrac{135}{55}\\\\x=\dfrac{27}{11}\\\\Answer:\ x=\dfrac{27}{11}\ and\ y=-\dfrac{57}{22}\to\left(\dfrac{27}{11},\ -\dfrac{57}{22}\right)

8 0
3 years ago
PLZ HELP NEED ANSWER QUICK
Elena L [17]
87+87+81+86+89+83+89= 602. Divided by 7 because that’s how many numbers there were is 86 and that is your mean/average.
7 0
3 years ago
Read 2 more answers
What is the length of side a? Round to the nearest tenth of an inch. Enter your answer in the box. ( Answer in Inches )
Jet001 [13]

Given:

Base of a right triangle = 7 in

Height of a right triangle = a

Hypotenuse = 16 in

To find:

The length of side a.

Solution:

Using Pythagoras theorem:

\text{Base}^2+\text{Height}^2=\text{Hypotenuse}^2

7^{2}+a^{2}=16^{2}

49+a^{2}=256

Subtract 49 from both sides.

49+a^{2}-49=256-49

a^{2}=207

Taking square root on both sides, we get

a = 14.4

The length of side a is 14.4 in.

3 0
3 years ago
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