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Arlecino [84]
3 years ago
14

How would I do this? Evaluate the expression: ₉P₄

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

3024

Step-by-step explanation:

It is basically asking how many ways you can order something so you're gonna need a calculator.

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Step-by-step explanation:

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3 years ago
Laws Of Indicies<br>Can someone please help me with this?​
nasty-shy [4]

Answer:

See below

Step-by-step explanation:

1) :  {a}^{5}  {b}^{4}  {c}^{3}  \div  {a}^{2}  {b}^{3} c \\  \\  = {a}^{5 - 2}  {b}^{4 - 3}  {c}^{3 - 1}  \\  \\  = {a}^{3}  {b}^{1}  {c}^{2}  \\  \\ = {a}^{3}  {b}  {c}^{2}  \\  \\  \\2)\:  (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4}   \div ( {a}^{2}  \times 3a) \\  \\  = 5 {a}^{4}   \div (3 {a}^{2 + 1}  ) \\  \\  = 5 {a}^{4}   \div (3 {a}^{3}  ) \\  \\  =   \frac{5}{3}  {a}^{4 - 3}  \\  \\ =   \frac{5}{3}  {a} \\  \\  \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4}  }  \\  \\  =   \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} }   \\  \\  =   \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} }    \\  \\  =   \frac{  {a}^{5} }{ {a}^{7} }   \\  \\  =  {a}^{5 - 7}  \\  \\  =  {a}^{ - 2}  \\  \\  =  \frac{1}{{a}^{2} }  \\  \\

8 0
3 years ago
Read 2 more answers
Can anyone plz solve this ?? -7 (1+3x) =4+5x
Aleonysh [2.5K]

Step-by-step explanation:

-7(1+3x) = 4 + 5x

-7 - 21x = 4 + 5x

(get all the variables on one side. Don't forget to change the signs)

-7-4 = 5x + 21x

-11 = 26x

(divide both sides by the coefficient [26])

26x/26= -11/26

x = -11/26

3 0
2 years ago
Jen spent $35 at the mall and now has $76 left. How much money did Jen have before she went shopping? Construct an equation to r
Levart [38]

Answer:

111

Step-by-step explanation:

x-35=76

x=111

4 0
3 years ago
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Given f(x) = –2 – 4, find f(4).
harkovskaia [24]

Answer:

-6

Step-by-step explanation:  6  6  15  40

f(x) = –2 – 4, find f(4)

since there is NO x term in the function for ANY x

f(4) = –2 – 4  = -6

f(any x) = –2 – 4, find f(-∞ = x = ∞)

            =  -6

3 0
3 years ago
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