With the b2+b- 12 your gonna want to do this
b2+b-12
b2+4b-3b-12
which is the sum product
after doing that you wanna common the factors from the two pairs. Which is b2+4b-3b-12 then you do you parentheses around b(b+4)-3(b+4) just like that after you do that then you rewrite it in factored form b(b+4)-3(b+4) you then want to rewrite it to this (b-3)(b+4) after that your solution will be (b-3)(b+4) for the first one.
Answer:
its d
Step-by-step explanation:
trust me
Well, here is how i would do it.
We start with 225, at a rate of 15% per year. Assuming your answers are in years and not months, we will increase by this increment; years.
So, we start with 225, and a 15%, or .15, increase. So what we would do, it take 225 times .15. One way ive learned to do this (via algebra class) is that you can times it by 1.15 to make it quicker, this just takes out the adding step.
So after one year, we would have a total of 258.75, or about 259 wolves.
after two years, we would have about 298 (we cant have a half of a wolf!)
after 3 years, we would have about 343 wolves.
after 4 years, we would have about 394 ish
after 5 years, we would have about 453
after 6 years, we would have about 521.
So, it would take about 5 and a half years, if thats an option choice.
Prime factorization: 96 = 2 x 2 x 2 x 2 x 2 x 3, which can also be written as 2⁵ x 3.
