B(t) = 5000 * 2^(-0.05t)
<span>2000 = 5000 * 2^(-0.05t) , div by 5000 </span>
<span>0.4 = 2^(-0.05t) , ln on both sides => </span>
<span>ln0.4 = (-0.05t)* ln2 </span>
<span>(ln0.4)/ln2) /(-0.05) = t </span>
<span>t = 26.43 </span>
<span>After 27 years</span>
Answer:
a. -12
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Define</u>
h(r) = (2/3)r - 6
h(-9) is r = -9
<u>Step 2: Evaluate</u>
- Substitute: h(-9) = (2/3)(-9) - 6
- Multiply: h(-9) = -6 - 6
- Subtract: h(-9) = -12
And we have our answer!
Answer:
3+i×root 3
Step-by-step explanation:
need thanks and make me brainiest if it helps you
Your equation is not dimensionally consistent.
Let L = length and T = time. Without taking into account precise units, you can write velocity as the ratio between some distance L and some time T.
So in terms of these fundamental quantities, your equation can be written as
L = (L/T + L/T)T^2
L = (L + L)T
L = LT
