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3 years ago

Pls help i ll mark brianiest

Mathematics

2 answers:

HACTEHA [7]3 years ago

8 0

Answer:

nEHdaskfidhsgiusdfhiughsdf

Step-by-step explanation:

vladimir1956 [14]3 years ago

5 0

Answer: ur answer would be D

Step-by-step explanation:

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11. SWIMMING Naira's home is located at the midpoint between the city

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Basketball court is half mile away and the distance between pool and basketball court is 1 mile.

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3 years ago

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3 years ago

What percent of 150 is 36?

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3 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

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3 years ago

What value of m does the graph y = 18x2 + mx + 2 have exactly one x-intercept?

Vlada [557]

To get the graph to have one x-intercept, we must find the m value where the discriminant of the equation will equal 0.

The discriminant for a graph with one x-intercept is found with the following formula:

$b^2 - 4ac = 0$

Plug in the values of the equation into this formula:

$\text{a = 18, b = m, c = 2}$
$m^2 - 4(18)(2) = 0$
$m^2 - 144 = 0$

Add 144 to both sides:

$m^2 = 144$

Square root both sides to get m by itself:

$\sqrt{144} = \pm 12$
$m = 12, \ m = -12$

In order for the graph to have one x-intercept, m must equal -12 or 12.

7 0

4 years ago