ANSWER:
- x – 3y = 2 ...(1)
- 2x – 6y = 6 ...(2)
On solving eq(1), we get
Plug the value of x in eq(2)
- 2x – 6(x - 2/3) = 6
- 2x – 2(x – 2) = 6
- 2x – 2x + 4 = 6
- 0 = 6 – 4
- 0 ≠ 2
So, given system of equations is not correct.
Multiply all the numbers together to get the total amount of possible outcomes
20 x 13 x 35 = 9100
There are 9100 possible outcomes that Becky can get
hope this helps
First chore, 6 to choose from.
Second chore, 5 to choose from.
Third chore, 4 to choose from.
Fourth chore, 3 to choose from.
Fifth chore, 2 to choose from.
Sixth chore, 1 to "choose" from.
The total number of orders possible is the product
6*5*4*3*2*1=6!=720
Four hundreds two tens and three ones
Solve for the x-max or h :\

plug it in to equation to get k:/

-8+16+3=11=k

solve for a by pluging (0,0)
then a= -11/4