F(x) = 3x² - 1
f(-2) = 3(-2)² - 1
f(-2) = 3(4) - 1
f(-2) = 12 - 1
f(-2) = 11
f(x) = x < 1
f(-2) = -2 < 1
f(x) = x + 2
f(-2) = -2 + 2
f(-2) = 0
f(x) = x > 1
f(-2) = -2 > 1
f(-2) = -2 < 1
Answer:
CU = 117
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
= 
substituting in values to the ratios
=
( cross- multiply )
24(36x - 1) = 3432 ( divide both sides by 24 )
36x - 1 = 143 ( add 1 to both sides )
36x = 144 ( divide both sides by 36 )
x = 4
CU = 36x - 1 - 26 = (36 × 4) - 27 = 144 - 27 = 117
<span> The surface area of a right prism can be calculated using the following formula: SA 5 2B 1 hP, where B is the area of the base, h is the height of the prism, and P is the perimeter of the base. The lateral area of a figure is the area of the non-base faces only.</span>
Answer:
1000. 100x10=1000 100+100+100+100+100+100+100+100+100+100=1000
100/1000=1/10
Step-by-step explanation:
Define
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s