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4 years ago

Factor the following polynomial completely. -x2y2 + x4 + 9y2 - 9x2

Mathematics

1 answer:

arsen [322]4 years ago

5 0

Factor by grouping, -x2y2+9y2= y2(-x2+9)
x4-9x2=- x2(-x2+9)
= (y2-x2)(-x2+9)

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Enrique left the study group traveling 20 mph. Then, 2 hours later, Tevin left traveling the same direction at 28 mph. How long

nadya68 [22]

Answer:

After 7 hours Tevin will catch Enrique

Step-by-step explanation:

We have given speed of Enrique is 20 mph

Tevin left traveling after 2 hours of Enrique

Speed of Tevin is 28 mph

When Tevin catches Enrique will cover same distance

Let Enrique is traveling for t hours

Then Tevin will travel for t-2 hours

We know that distance = speed × time

So $20\times t=28\times (t-2)$

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t = 7 hours

So after 7 hours Tevin will catch Enrique

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4 years ago

Sophie [7]

Answer:

Step-by-step explanation:

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3 years ago

Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

Answer: The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

Step-by-step explanation:

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

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