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alexandr1967 [171]
3 years ago
7

Which example would represent a negative number? Question 5 options: spending money gaining weight the temperature rising having

a birthday
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0
Spending money, since your amount of money is decreasing, which is negative
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What are the steps to divide 36.75 by 3?
Nadya [2.5K]

Answer:

12.25

Step-by-step explanation:

(1): "36.75" was replaced by "(3675/100)".

2 Simplify 147/4

3 147 /4 divided by 3

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49/4 which equal 12.25000

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2 years ago
What is the unit rate of the proprrional relationship represented by the equation y=3x
NeX [460]

The unit rate of the proportional relationship y = 3x is 3

<h3>How to determine the unit rate?</h3>

The proportional relationship is given as:

y = 3x

Divide both sides by x

y/x = 3

For a proportional relationship y/x = k;

The unit rate is 3

This means that the unit rate of the proportional relationship y = 3x is 3

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2 years ago
The constant in the expression 8x 3 + 4x 2 – 9 is
Ket [755]

Answer : 9

Step-by-step explanation:

The answer is 9 because a constant is a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number.

6 0
3 years ago
Draw the multiplication table on the P=(3,5,7,9) in module 12​
Lisa [10]

Answer:

Find the attached file for the solution

Step-by-step explanation: To draw the multiplication table on the P=(3,5,7,9) in module 12, create the table where all the given parameters will be at the top of horizontal axis and vertical axis,

When multiply by each other, any value that is below 12 will be written down while the value greater than 12 will be divided by 12 and the remainder will be written down.

Find the attached file for the solution and table.

8 0
2 years ago
"Solving Equations by Completing the Square: m^2+2m-48=-6
kvv77 [185]
m^2+2m-48=-6 \\ \\ m^2+2m-48+6=0\\ \\m^2+2m-42=0\\ \\a=1, \ b= 2, \ c= -42 \\ \\\Delta = b^{2}-4ac = 2^{2}-4*1*(-42)= 4+168 =172 \\\\\sqrt{\Delta }=\sqrt{172} =\sqrt{4*43}=2\sqrt{43}\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-2-2\sqrt{43}}{2}=\frac{2(-1-\sqrt{43})}{2}= -1-\sqrt{43} \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} = \frac{-2+2\sqrt{43}}{2}=\frac{ 2(-1+\sqrt{43})}{2}= -1+\sqrt{43}
5 0
2 years ago
Read 2 more answers
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