<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
-29/6
Step-by-step explanation:
1 1/6=7/6
-3 2/3=-11/3
-11/3-7/6
-22/6-7/6=-29/6
Point c is the point hope this helps
Of the 5 routes Tanya can choose from, 2 routes will take 30 minutes. This means that the probability is:
2/5 = 0.4
The answer is 40%.
Answer:
Step-by-step explanation:
<u>Simplify the numerator:</u>
- 1/x² + 2/y =
- y/(x²y) + 2x²/(x²y) =
- (2x² + y)/(x²y)
<u>Simplify the denominator:</u>
- 5/x - 6/y² =
- 5y²/(xy²) - 6x/(xy²) =
- (5y² - 6x) / (xy²)
<u>Simplify the fraction:</u>
- (2x² + y)/(x²y) ÷ (5y² - 6x) / (xy²) =
- (2x² + y)/(x²y) × xy² / (5y² - 6x) =
- y(2x² + y) / x(5y² - 6x)
