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Aleonysh [2.5K]

3 years ago

7

a box of mass 3kg is lifted 1.5 m onto a shelf. calculate the change in its gravitational potential energy. the gravitational fi

eld strength is 10 N/kg

1 answer:

victus00 [196]3 years ago

4 0

Potential energy due to gravity= mass x gravity x height

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2 general categories of factors that determine how we look and behave, and how do they influence us?

Setler79 [48]

Answer:

Good question. The answer is abilities. or gender

Explanation:

6 0

3 years ago

21.49 .. A charge of -6.50 nC is spread uniformly over the surface of one face of a nonconducting disk of radius 1.25 cm. (a) Fi

AnnyKZ [126]

Explanation:

It is given that,

Charge, $q=-6.5\ nC=-6.5\times 10^{-9}\ C$

Radius of the disk, R = 1.25 cm = 0.0125 m

(a) Electric field at a distance of 2 cm from the center of the disk. It can be calculated using the formula as :

$E=\dfrac{\sigma}{2\epsilon_o}[1-\dfrac{x}{\sqrt{x^2+R^2}}]$

Where

$\sigma$ is the surface charged density, $\sigma=\dfrac{q}{\pi r^2}$

$\sigma=\dfrac{-6.5\times 10^{-9}}{\pi (0.0125)^2}$

$\sigma=-1.32\times 10^{-5}\ C/m^2$

So, $E=\dfrac{1.32\times 10^{-5}}{2\times 8.85\times 10^{-12}}[1-\dfrac{0.02}{\sqrt{0.02^2+0.0125^2}}]$

$E=-1.13\times 10^5\ N/C$

The direction of electric field is outwards.

(b) Suppose that the charge were all pushed away from the center and distributed uniformly on the outer rim of the disk. So, the electric field due to the ring is :

$E=\dfrac{kqx}{(x^2+R^2)^{3/2}}$

$E=\dfrac{9\times 10^9\times -6.5\times 10^{-9}\times 0.02}{(0.02^2+0.0125^2)^{3/2}}$

$E=-8.91\times 10^4\ N/C$

The direction of electric field is outwards.

(c) If the charge is all brought to the center of the disk, The electric field at the center of disk is given by :

$E=\dfrac{kq}{R^2}$

$E=\dfrac{-9\times 10^9\times -6.5\times 10^{-9}}{0.02^2}$

$E=-1.46\times 10^5\ N/C$

(d) he field in part (a) stronger than the field in part (b). This is due to the reason that the charge at the center of the ring is 0.

(e) The field in part (c) the strongest of the three fields because the for a point charge the charges are at same distances.

7 0

4 years ago

An N-slit system has slit separation d and slit width a. Plane waves with intensity I and wavelength O are incident normally on

Leokris [45]

Answer:

E. d and O

Explanation:

"Light passing through a single slit forms a diffraction pattern somewhat different from those formed by double slits or diffraction gratings".

According to Huygens’s principle, "for each element of the wavefront in the slit emits wavelets. These are like rays that start out in phase and head in all directions. (Each ray is perpendicular to the wavefront of a wavelet.) Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel".

The destructive interference for a single slit is given by:

$d sin \theta = m\lambda , m=1,-1,2,-2,3,...$

Where

d is the slit width

$\lambda=O$ is the light's wavelength

$\theta$ is the angle relative to the original direction of the light

m is the order od the minimum

I represent the intensity

When the intensity and the wavelength are incident normally the angular as we can see on the expression above the angular separation just depends of the distance d and the wavelength O.

7 0

3 years ago

A bungee jumper with mass 63.0 kg jumps from a high bridge. After reaching his lowest point, he oscillates up and down, hitting

fomenos

Answer:

80.6 N/m

Explanation:

mass (m) = 63 kg

time (s) = 44 s

number of oscillations (n) = 8

stretched length of the cord (L) = 23 m

we can calculate the spring constant of the cord from the formula below

f = $\frac{1}{2π}$ x $\sqrt{\frac{k}{m} }$ ...equation 1

where

f = frequency

k = spring constant

m = mass

frequency = $\frac{number of oscillation}{time}$

frequency = $\frac{8}{44}$ = 0.18

now we can input all the required values into the equation 1

0.18 = $\frac{1}{2π}$ x $\sqrt{\frac{k}{63} }$

0.18 x 2π = $\sqrt{\frac{k}{63} }$

1.13 = $\sqrt{\frac{k}{63} }$

$1.13^{2}$ = $\frac{k}{63}$

k = 63 x 1.28 = 80.6 N/m

5 0

3 years ago

run at the same speed and in the same direction, and they both run for the same amount of time, what can you say about the dista

LenaWriter [7]

Answer:

the are equivalent

Explanation:

i just learned about that

4 0

4 years ago