D =√(x2-x1)^2 + (y2-y1)^2
......._____________
5 =√(3-0)^2 + (k-1)^2
.......__________
5 =√3^2 + (k-1)^2
25 = 9 + (k-1)^2
16 = k^2 - 2k + 1
k^2 -2k - 15 = 0
(k - 5)(k + 3) = 0
k - 5 = 0.....or.......(k + 3) = 0
k = 5.........or.......k = -3
Answer:
The equation of the line is
2y=x+8
Step-by-step explanation:
This is a straight line graph.
And general equation of a straight is given by
y=mx+c
Where m is slope
c is the intercept on y axis at x=0
So at y=0, x=8. This is from the graph.
And inserting this value of y and x into the straight line equation
y=mx+c
0=-8m+c
Therefore, c=8m. Equation 1
Taking another point on the graph
at=0, y=4
Also, inserting this value of y and x into the straight line equation
4=0×x+c
4=0+c
Therefore, c=4.
Therefore the intercept is 4
From equation 1
c=8m c=4
Then m=c/8
m=4/8
m=1/2
Then the equations of then line is
y=mx+c
y=(1/2)x+4
Multiply through by 2
2y=x+8
The equation of the line is
2y=x+8
All you have to do is divide 321 by 3 to get $107.00 each night
The system of equations has one solution (-1, 1)
<h3>Graph of system of linear equations </h3>
From the question, we are to graph the given system of equations.
The given system of equation is
y + 2x = −1
3y − x = 4
The graph of the given system of equations is shown below.
From the graph, we can observe that the solution to the given system of equation is given by two lines that intersect at the point (-1, 1).
Hence, the system of equations has one solution (-1, 1)
Learn more on Graph of linear equations here: brainly.com/question/14323743
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