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I am Lyosha [343]
3 years ago
5

Estimate product using compatible numbers 0.67 x 623

Mathematics
1 answer:
alekssr [168]3 years ago
8 0
It could possible be 417. 
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consider the expression (2m + n - 5) and (-3 - 5m + 6n) what is the sum of the expression for n = -3 and m =6​
Mademuasel [1]

Answer:

Need more info

Is this supposed to be two different sums for each expression in each sets of ()

or are they together? like is each set multiplied together?

4 0
3 years ago
Find all polar coordinates of point p where p = ordered pair 5 comma pi divided by 3.
Aleonysh [2.5K]

Find all polar coordinates of point p where p = ordered pair 5 comma pi divided by 3.

The polar coordinate of any point can be written as:

<span>(r, θ) = (r, θ + 2nπ)                                           --> when positive</span>

<span> (r, θ) = [ - r, θ + (2n + 1)π ]                           --> when negative</span>

<span> where n is any integer.</span>

The polar coordinates of this given point P is: P = (r, θ) = (5, π/3).

When the value of r is positive, the polar coordinate is written as P= (5, π/3) = (5, π/3 + 2nπ)

where n is any integer.

When the value of r is negative, the polar coordinate is written as P = (5, π/3) = [ - 5, π/3 + (2n + 1)π] where n is any integer.

 

Therefore all polar coordinates of point P are (5, π/3 + 2nπ) and [ - 5, π/3 + (2n + 1)π ].

<span> </span>

7 0
3 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
A cereal manufacturer decides to offer a new family-sized box based on the regular-sized box. They want the volume of the family
Pani-rosa [81]
The answer would be an increase by a factor of 3/2
4 0
2 years ago
Read 2 more answers
Solve using the quadratic formula
Novay_Z [31]

Answer: 5.17, -0.67


Step-by-step explanation: Solve the equation for p by finding a, b, and c of the qudratic then applying the qquadratic formula

Excact Form: p = 9 + √137/4, 9 - √137/4

Decimal Form:

p = 5.17617497 . . . , -0.67617497 . . .

Hope this helps! :)

~Zane


4 0
3 years ago
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