Question

What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

Answer 1

Answer:

The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

Step-by-step explanation:

We know that the slope intercept-form of the line equation is

$y=mx+b$

where m is the slope and b is the y-intercept

Given the equation

$6x+3y=-63$

simplifying the equation to write in the slope-intercept form

$y=-2x-21$

Thus, the slope = -2

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be:

$\frac{-1}{-2}=\frac{1}{2}$

Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

Answer 2

Answer:

y=x/2−63

Step-by-step explanation:  6x+3y=-63     3y=6x-63= y=2/x-63