What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63
2 answers:
Answer:
The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2
Step-by-step explanation:
We know that the slope intercept-form of the line equation is
where m is the slope and b is the y-intercept
Given the equation
simplifying the equation to write in the slope-intercept form
Thus, the slope = -2
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
The slope of the perpendicular line will be:
Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2
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9514 1404 393
Answer:
10s place
Step-by-step explanation:
When you line up the three digits of the divisor with the three most significant digits of the dividend, you see that the least significant digit of the divisor lines up with the dividend digit that is in the 10s place.
The first (most-significant) quotient digit will be in the 10s place.
_____
In the attached, the left-most non-zero quotient digit is 4, in the tens place.
Answer:
0.6 seconds to 2.6 seconds
Step-by-step explanation:
From the graph the ball reaches 28 feet after 0.574 seconds
and doesn't fall below that until 2.614 seconds
0.574 rounded is 0.6 seconds
2.614 rounded is 2.6 seconds
