What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63
2 answers:
Answer:
The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2
Step-by-step explanation:
We know that the slope intercept-form of the line equation is
where m is the slope and b is the y-intercept
Given the equation
simplifying the equation to write in the slope-intercept form
Thus, the slope = -2
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
The slope of the perpendicular line will be:
Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2
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now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.
let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.
