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kherson [118]
3 years ago
10

Fraction from or decimal form but has to be rounded

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0

Answer:

x = \frac{25}{6}

Step-by-step explanation:

Given expression is,

2x-\frac{11}{4}x=-\frac{25}{8}

\frac{8x}{4}-\frac{11}{4}x=-\frac{25}{8}

\frac{8x-11x}{4}=-\frac{25}{8}

-\frac{3x}{4}=-\frac{25}{8}

\frac{3x}{4}\times 4=\frac{25}{8}\times 4

3x=\frac{25}{2}

\frac{3x}{3}=\frac{25}{2}\times \frac{1}{3}

x = \frac{25}{6}

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Answer:

Local minimum at x = 0.

Step-by-step explanation:

Local minimums occur when g'(x) = 0 and g"(x) > 0.

Local maximums occur when g'(x) = 0 and g"(x) < 0.

Set g'(x) equal to 0 and solve:

0 = 2x (x − 1)² (x + 1)²

x = 0, 1, or -1

Evaluate g"(x) at each point:

g"(0) = 2

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g"(-1) = 0

There is a local minimum at x = 0.

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3 years ago
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Bc¯¯¯¯¯ is parallel to de¯¯¯¯¯. what is ab? enter your answer in the box.
svetlana [45]
This can help you to understand it

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Task 2 a. Do some research and find a city that has experienced population growth. Determine its population on January 1st of a
Galina-37 [17]

Exponential functions are functions defined by y = ab^x, where a represents the initial value, and b represents the rate

<h3>The equation of a city that has experienced a population growth</h3>

The initial population of the city is 10000, and the growth rate of the population is 4%.

So, the exponential equation is:

y = 10000 * 1.04^x

<h3>The equation of a city that has experienced a population decline</h3>

The initial population of the city is 12000, and the decay rate of the population is 3%.

So, the exponential equation is:

y = 12000* 0.97^x

<h3>The similarities in the equations</h3>

The similarity in both equations is that, they both represent exponential function.

<h3>The year the population of city A exceeds B</h3>

In (a) and (b), we have:

y = 10000 * 1.04^x ---- city A

y = 12000* 0.97^x --- city B

When city A exceeds city B, we have the following inequality

10000 * 1.04^x > 12000 * 0.97^x

Divide both sides by 10000

1.04^x > 1.2 * 0.97^x

Divide both sides by 0.97^x

(\frac{1.04}{0.97})^x > 1.2

1.07^x > 1.2

Take the natural logarithm of both sides

\ln(1.07)^x > \ln(1.2)

This gives

x\ln(1.07) > \ln(1.2)

Solve for x

x > \frac{\ln(1.2)}{\ln(1.07)}

x > 2.69

This means that, the population of city A will exceed city B after 3 years

<h3>The year the population of city A will be at least twice of city B</h3>

In (a) and (b), we have:

y = 10000 * 1.04^x ---- city A

y = 12000* 0.97^x --- city B

When city A is at least twice city B, we have the following inequality

10000 * 1.04^x \ge 2 * 12000 * 0.97^x

10000 * 1.04^x \ge 24000 * 0.97^x

Divide both sides by 10000

1.04^x \ge 2.4 * 0.97^x

Divide both sides by 0.97^x

(\frac{1.04}{ 0.97})^x \ge 2.4

1.07^x \ge 2.4

Take the natural logarithm of both sides

\ln(1.07)^x \ge \ln(2.4)

This gives

x\ln(1.07) \ge \ln(2.4)

Solve for x

x\ge \frac{\ln(2.4)}{\ln(1.07) }

x\ge 12.9

This means that, the population of city A will be at least twice city B after 13 years

Read more about exponential functions at:

brainly.com/question/11464095

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3 years ago
C
ddd [48]

Answer:

second option is the answer of your question

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