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fomenos
3 years ago
11

During a sale, a dress decreased in price from $90 to &63. What was the percent of decrease?

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0
%change=100(final-initial)/initial

%change=100(63-90)/90

%change= -30%

So the price was decreased by 30%
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Use slopes and y-intercepts to determine if the lines 6x+y=−1 and −2x−5y=1 are parallel.
kobusy [5.1K]

Answer:

The two lines are not parallel.

Step-by-step explanation:

Every linear equation follows this structure:

y = mx + b

y is the y value

x is the x value

m is the gradient/slope of the line

b (or sometimes c) is the y-intercept of the line

Firstly, we have to get the y term on one side by itself.

6x + y = -1

-6x        -6x

y = -6x - 1

-2x -5y = 1

+2x         +2x

-5y = 2x + 1

Secondly, we make it so the y term is just the y value.

The first equation is already like this, so we don't need to do anything to that.

-5y = 2x + 1

÷ -5  ÷ -5

y = (2x + 1) / -5

This can be expanded and simplified to:

y = -2/5x - 1/5

Thirdly, we have to compare the slopes and y-intercepts.

y = -6x - 1

y = 2/5x - 1/5

If the slopes are the same and the y-intercepts are different, they are parallel. However, the slopes are different, therefore they are not parallel.

7 0
3 years ago
Find yhe difference 2/5 - 3/10
sp2606 [1]
You need common denominators to add or subtract fractions. If you multiple (2/5) by 2 to both the top and bottom, you get (4/10). Now you just subtract the top numbers, or numerators. 4 - 3 = 1. Answer: 1/10.
4 0
3 years ago
Read 2 more answers
The circumference of a circle is 15.2mm.
bulgar [2K]

Answer:

circumference of circle (c)=15.2mm

length of radius (r)=?

we know,

c= 2×pi×r=2×3.14×r

or,15.2/6.28=r

or,2.4=r

2.4mm=r

5 0
3 years ago
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it use
evablogger [386]

Answer:

(1)  Null Hypothesis, H_0 : \mu_1 = \mu_2

    Alternate Hypothesis, H_1 : \mu_1\neq \mu_2

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let \mu_1 = mean annual family income for 12 people making inquiries at the first development

\mu_2 = mean annual family income for 24 people making inquiries at the second development

s_1 = standard deviation of annual family income for 12 people making inquiries at the first development

s_2 = standard deviation of annual family income for 24 people making inquiries at the second development

n_1 = sample of people of first development i.e. 12

n_2 = sample of people of second development i.e. 24

(1) Null Hypothesis, H_0 : \mu_1 = \mu_2  {population means are same}

  Alternate Hypothesis, H_1 : \mu_1\neq \mu_2  {population means are different}

<u>DECISION RULE ;</u>

  • If the test statistics is less than the critical value of t from table at 5% significance level, then we will accept null hypothesis, H_0 .
  • If the test statistics is more than the critical value of t from table at 5% significance level, then we will reject null hypothesis, H_0 .

(2) The test statistics is given by;

                      \frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where,  X_1bar = Sample mean income of people at first development

                        = $153,000

X_2bar = Sample mean income of people at second development = $171,000  

s_1 = $42,000  and   s_2 = $30,000

   s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2}} =  \sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2}  }{12+24-2}} = 34344.30

Test statistics = \frac{(153000 -171000) - 0}{34344.30\sqrt{\frac{1}{12}+\frac{1}{24}  } } ~ t_3_4

                       = -1.48

(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

4 0
4 years ago
50 points, question is below.
REY [17]

x^2+3x-10\neq0\\\\x^2+5x-2x-10neq0\\\\x(x-5)-2(x+5)\neq0\\\\(x+5)(x-2)\neq0\to x+5\neq0\ \wedge\ x-2\neq0\\\\x\neq-5\ \wedge\ x\neq2\\\\\dfrac{x+5}{x^2+3x-10}=\dfrac{x+5}{(x+5)(x-2)}=\dfrac{1}{x-2}\\\\Answer:\ x=2

8 0
3 years ago
Read 2 more answers
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