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SOVA2 [1]
2 years ago
14

5

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
7 0

Answer:

The right answer is:

Option OB: f(1) = -9

Common difference: 7

Step-by-step explanation:

Given sequence is:

-9, -2, 5, 12,...

Here the first number is f(1)

Common Difference:

Common difference is the difference between consecutive terms of an arithmetic sequence. It is denoted by d.

In the given sequence,

f(1) = -9

f(2) = -2

f(3) = 5

d=f(2)-f(1) = -2-(-9) = -2+9 = 7\\d = f(3)-f(2) = 5-(-2) = 5+2 = 7

Hence,

The right answer is:

Option OB: f(1) = -9

Common difference: 7

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Which of the following is equivalent to 10 3/2?
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A model rocket is launched with an initial velocity of 250 ft per second. The height h, in feet, of the rocket t seconds after t
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9514 1404 393

Answer:

  {2.96, 12.66}

Step-by-step explanation:

A graph shows the rocket will be 600 feet up after 2.96 seconds, and again at 12.66 seconds.

__

You can solve the equation h = 600 to find the times.

  -16t^2 +250t = 600

  -16(t^2 -15.625t) = 600

  -16(t^2 -15.625t +7.8125²) = 600 -16(7.8125²)

  -16(t -7.8125)² = -376.5625

  t -7.8125 = √(376.5625/16) ≈ ±4.8513

  t = 7.8125 ± 4.8513 ≈ {2.9612, 12.6638}

The rocket will be 600 ft above the ground 2.96 and 12.66 seconds after launch.

4 0
2 years ago
A sphere rolls up an inclined plane of inclination angle 30 degree. At the bottom of the incline the center of mass of the spher
Zigmanuir [339]

Answer: The sphere is 0.002548 cm travel up the plane.

Step-by-step explanation:

Since we have given that

Inclination angle = 30°

Translational speed = 0.25 m/s

As we know that

KE=0.5\times lw^2=PE

and

Length of solid sphere is given by

l=\dfrac{2Mr^2}{5}

So, it becomes,

KE=0.5\times \dfrac{2Mr^2}{5}w^2=Mgd\sin \theta

And 0.25\ m/sv=rw

So, it becomes,

1\times (0.25)^2=5\times d\times 9.81\times \sin 30^\circ\\\\0.0625=49.05d\times \dfrac{1}{2}\\\\\dfrac{0.125}{49.05}=d\\\\d=0.002548

Hence, the sphere is 0.002548 cm travel up the plane.

5 0
3 years ago
The perimeter of the big wheel of a bicycle is 9 cm longer than the perimeter of the front wheel. On the road of 120 cm, the big
beks73 [17]

Answer:

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Search for questions & chapters

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Question

Bookmark

A boy is cycling such that the wheels of the cycle are making 140 revolutions per minute. If the diameter of the wheel is 60cm, calculate the speed per hour with which the boy is cycling.

Easy

Solution

verified

Verified by Toppr

Radius of the wheel =r=

2

60

=30 cm

Circumference of the wheel =2πr=2×

7

22

×30=

7

1320

cm

Distance covered in 1 revolution =

7

1320

cm

Distance covered in 140 revolutions =

7

1320

×140=26400 cm=264 m=

1000

264

km

Distance covered in one minute = Distance covered in 140 revolutions =

1000

264

km

Distance covered in 1 hour =

1000

264

×60=15.84 km

Hence, the speed with which the boy is cycling is 15.84km/hr.

3 0
2 years ago
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