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SOVA2 [1]
2 years ago
14

5

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
7 0

Answer:

The right answer is:

Option OB: f(1) = -9

Common difference: 7

Step-by-step explanation:

Given sequence is:

-9, -2, 5, 12,...

Here the first number is f(1)

Common Difference:

Common difference is the difference between consecutive terms of an arithmetic sequence. It is denoted by d.

In the given sequence,

f(1) = -9

f(2) = -2

f(3) = 5

d=f(2)-f(1) = -2-(-9) = -2+9 = 7\\d = f(3)-f(2) = 5-(-2) = 5+2 = 7

Hence,

The right answer is:

Option OB: f(1) = -9

Common difference: 7

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If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?
Irina18 [472]

Answer:

36

Step-by-step explanation:

Hello,

If X=x^2 it becomes

X^3-289X^2-X+289=(X^2-1)(X-289)

and 289=17^2

X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)

So,

x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

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