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leva [86]
3 years ago
15

What is the perimeter of a triangle ABC With Vertices A(-1,3) B(2,3) C (-1,-3)

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0

Answer:

15.71

Step-by-step explanation:

Length AB =  sqrt ( (3-3)^2 + (2- - 1)^2) =  sqrt9 = 3

Length BC =  sqrt ( (-3-3)^2 + ( -1-2)^2) =  sqrt  45

Lemgth CA =  sqrt( 6^2) + (-1 - -1)^2 = sqrt 36 = 6

Perimeter = 3 + 6 + sqrt45

= 15.71

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