Question

What is the perimeter of a triangle ABC With Vertices A(-1,3) B(2,3) C (-1,-3)

Answer 1

Answer:

15.71

Step-by-step explanation:

Length AB =  sqrt ( (3-3)^2 + (2- - 1)^2) =  sqrt9 = 3

Length BC =  sqrt ( (-3-3)^2 + ( -1-2)^2) =  sqrt  45

Lemgth CA =  sqrt( 6^2) + (-1 - -1)^2 = sqrt 36 = 6

Perimeter = 3 + 6 + sqrt45

= 15.71