Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
X=<span><span><span>43</span>y</span>+<span><span>−4</span><span>3 hope this helped</span></span></span>
Answer:
b
Step-by-step explanation:
u just have to think about it
A= 100; b= 0,9
f(x)= 100.(0,9)^x
Answer:
9:130 10:198 11:76
Step-by-step explanation:
S.A.:= 2LW+2LH+2WH
