It is necessary to declare the function as a member of the class that overloads the ->c operator for the class.
<h3>What does C's -> operator mean?</h3>
- In C/C++, the Arrow operator makes it possible to access items in unions and structures.
- It is used in conjunction with a pointer variable pointing to a union or structure.
- As demonstrated below, the arrow operator is created by utilizing a negative sign and the greater than symbol.
- (Pointer name)->(Variable Name) is the syntax.
- To access members of a class, structure, or union using a pointer, use the -> (arrow) operator.
- A member of the object to which the pointer points is designated by a postfix expression, a -> (arrow) operator, followed by a potential qualified identifier or a pseudo-destructor name.
Therefore the correct answer is, c. ->
The complete question is:
The function that overloads the ____ operator for a class must be declared as a member of the class.
a. ::
b. *
c. ->
d. +
To learn more about -> operator, refer to:
brainly.com/question/13814474
#SPJ4
Answer:
SMTP
Explanation:
This is the SMTP or the Simple Mail Transfer Protocol. It is the push protocol and is used to send the mail message. Whereas POP3 and IMAP are meant for retrieving the message. These are the three main types of protocols associated with mail services. And the correct answer here is certainly the SMTP.
<span>Consider
the cement used for the foundation; the bricks and timber used for the
walls; and the shingles used for the roof. All of these are __________
in making the house.
A. Elements</span>
Answer:
Good choice, as its one of the most secure wireless communications encryption methods, even though WPA2 would be the best
Explanation:
One of the founders of Foursquare is Dennis Crowley. The other is Naveen Selvadurai. I know you didn't ask for both but I wanted to give them to you just in case. I hope this helps! (:
