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julsineya [31]
2 years ago
5

in an examination 60% exam in failed in maths 55% failed in English and 25 failed in both subjects if none of the exam in past i

n the both subject find the number of exam in who passed in mathematics only​
Mathematics
1 answer:
masha68 [24]2 years ago
4 0

Answer:

60% x 25

55 % x 25

10 in english

25 is total and rest will be math

so 25-10 = 15

15 students failed math

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The annual rainfall (in inches) in a certain region is normally distributed with mean 43.2 and variance 20.8. Assume rainfall in
Wittaler [7]

Answer:

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

\mu = 43.2, \sigma = \sqrt{20.8} = 4.56

Probability that a year has rainfall of more than 50 inches.

pvalue of Z when X = 50. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 43.2}{4.56}

Z = 1.49

Z = 1.49 has a pvalue of 0.9319

1 - 0.9319 = 0.0681

Find the probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

This is P(X \leq 2) when n = 15, p = 0.0681. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.0681)^{0}.(0.9319)^{15} = 0.3472

P(X = 1) = C_{15,1}.(0.0681)^{1}.(0.9319)^{14} = 0.3805

P(X = 2) = C_{15,2}.(0.0681)^{2}.(0.9319)^{13} = 0.1947

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.3472 + 0.3805 + 0.1947 = 0.9224

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

8 0
3 years ago
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Can someone give me answers pls asap
GuDViN [60]

Answer:

answers are:

1) 1.75

2) 1.25

6 0
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