Answer:
0.1855
Step-by-step explanation:
Assuming normal distribution, Sampling mean = $190
Sampling standard deviation =
= $2
a) Probability that the average annual cost of a random sample of 100 such checking accounts at U.S. community banks is less than $187 = P(X < 187)
= P(Z < (187 - 190)/2)
= P(Z < -1.5)
= 0.0668
b) Probability that the average annual cost of a random sample of 100 such checking accounts at U.S. community banks is more than $193.5
= 1 - P(X < 193.5)
= 1 - P(Z < (193.5 - 190)/2)
= 1 - P(Z < 1.75)
= 1- 0.9599
= 0.0401
c) Probability that the average annual cost of a random sample of 100 such checking accounts at U.S. community banks is between $191.70 to 194.5 = P(X < 194.5) - P(X <191.7)
= P(Z < (194.5 - 190)/2) - P(Z < (191.7-190)/2)
= P(Z < 2.25) - P(Z < 0.85)
= 0.9878 - 0.8023
= 0.1855
Answer:
an = 17n - 46
a50 = 804
Step-by-step explanation:
-29, -12, 5, 22, ...
Subtract each number from the next one.
-12 - (-29) = 17
5 - (-12) = 17
22 - 5 = 17
The common difference is 17. This is an arithmetic sequence which starts with -29, and in which each subsequent value is 17 more than the previous value.
a1 = -29
a2 = -29 + 17
a3 = -29 + 2(17)
a4 = -29 + 3(17)
Notice that for each term, you have -29 and something added to it. What you add to -29 is 17 multiplied by 1 less than the number of the term. For term 1, 1 less than 1 is 0. You add 0 * 17 to -29 and get -29. term 1 is -29. For term 2, 1 less than 2 is 1. You add 1 * 17 to -29 and get -12, etc.
For term n, 1 less than n is n - 1. Add (n - 1) * 17 to -29 to get term n.
an = -29 + 17(n - 1)
This formula can be simplified.
an = -29 + 17n - 17
an = -46 + 17n
an = 17n - 46
a50 = 17(50) - 46
a50 = 804
45. Using order of operations.
1.) Divide the value of the grilled cheese food cart by $100
$90,000 / $100 = $900
2.) Multiply the quotient by the rate per $100
$900 * $.83 = $747
3.) Therefore, B. $747 is Pedro's premium for his grilled cheese food cart
Answer:
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