I’m pretty sure the anser is b
Answer:
The degree is one for f, g, and h.
Step-by-step explanation:
we are given with a circle with the center at (3,3) and one that passes through (6,5). The equation of a circle is (x-h)^2 + (y-k)^2 = r^2. In this case h = 3 and k = 3. Substituting, h and k and x = 6 and y = 5, r^2 is obtained to be 13. Among these points, A. point (1,6) fits to the equation.
The first box is "none of these" since it is not a vertical angle, is not an adjacent angles, and is not a linear pair, the second box is vertical angles
For this we must use foil and multiply
4*6
4*-5i
-i*6
-i*-5i
to get (respectively to above)
24
-20i
-6i
5i^2
combine all of those to get:
24-26i+5i^2
now, i squared is equal to -1, so we can simplify the above even further:
24-26i+5(-1)
24-26i-5
19-26i
Now, that would be your final answer. But if you want it in radical form you would get this: (just so you know, i is the square root of -1, or an imaginary number)