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Jlenok [28]
3 years ago
10

Can someone help me pleaseeee

Mathematics
1 answer:
Flura [38]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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3 years ago
Media aritmetica a 3 nr este 24 . Al doilea numar e cu 50% mai mare decat primul iar al treilea este cu o treime mai mare decat
stepan [7]

Answer:

The numbers are 16,24 and 32

Step-by-step explanation:

<u><em>The question in English is</em></u>

The arithmetic mean of 3 numbers is 24. The second number is 50% greater than the first and the third is one third greater than the second. What are the numbers?

Let

x---> the first number

y ---> the second number

z ---> the third number

we know that

The arithmetic mean of 3 numbers is 24

so

\frac{x+y+z}{3}=24

x+y+z=72 ----> equation A

The second number is 50% higher than the first

Remember that

100\%+50\%=150\%=150/100=1.50

so

y=1.5x

x=\frac{2}{3}y ----> equation B

The third number is is one third greater than the second

Remember that

1+\frac{1}{3}=\frac{4}{3}

so

z=\frac{4}{3}y ----> equation C

substitute equation B and equation C in equation A

\frac{2}{3}y+y+\frac{4}{3}y=72

solve for y

3y=72\\y=24

Find the value of x

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Find the value of z

z=\frac{4}{3}(24)=32

therefore

The numbers are

16,24 and 32

4 0
3 years ago
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