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kramer
2 years ago
6

An investment had return of 13% if inflation was 4.1% what was your real return ?

Mathematics
1 answer:
e-lub [12.9K]2 years ago
8 0

Answer: 8.9%

Step-by-step explanation: 13 - 4.1

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How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98
Irina18 [472]

Answer:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=1400 represent the sample standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

8 0
4 years ago
Gavin drank 4 5 liter of water Monday before going jogging. He drank 2 3 liter of water after his jog. How much water did Gavin
Hoochie [10]

Answer:

<h2>8.0 liters</h2>

Step-by-step explanation:

The question is not well-formatted, this is supposed to be the correct format

<em>Gavin drank 4.5 liter of water Monday before going jogging. He drank 2.3 liter of water after his jog. How much water did Gavin drink altogether? Write your answer as a mixed number.</em>

Given

we are told that he first drank 4.5 liters of water before jogging

after jogging he drank 2.3 liters

Required

Total amount of water drank

=4.5+3.5

=8.0liters

5 0
3 years ago
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