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zhannawk [14.2K]
3 years ago
12

HELP ME I NEED HELP!!!!

Mathematics
1 answer:
eduard3 years ago
7 0

Answer:

D

Step-by-step explanation:

Since they are the same variables

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Help me with this please!!!!
sveticcg [70]

Answer:

option c is the correct answer

6 0
3 years ago
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Can you simplify 3/18. EXPLAIN?
Sauron [17]

Answer:

Yes, it simplifies to 1/6.

Step-by-step explanation:

Both the top (numerator) and bottom (denominator) can be both divided by 3.  3 divided by 3 is 1. 18 divided by 3 is 6.

3 0
3 years ago
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Amy and Stephanie were playing a number game. Amy picked a number and told Stephanie that if she added 9 to the number and multi
mrs_skeptik [129]

Answer:

A. 2(x + 9) = 8

Step-by-step explanation:

To solve this problem, we proceed as follows:

- We call "x" the number picked up by Amy:

x

- Amy then adds 9 to this number, so we get:

x+9

- Then, we multiply this sum by 2, so we get:

2(x+9)

- Finally, Amy says that this number is equal to 8:

2(x+9)=8

So the correct equation is

A. 2(x + 9) = 8

We can even solve it to find the number. We get:

2(x+9)=8\\2x+2\cdot 9 = 8\\2x+18=8\\2x+18-18=8-18\\2x=-10\\x=\frac{-10}{2}=-5

5 0
3 years ago
Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
Reagan used 1,221 sq ft of wrapping paper to wrap gifts for everyone in her class. If each gift used the same amount of wrapping
ipn [44]
She used 1221 wrapping paper for 21 gifts, so to find the individual amount, you would do:
1221/21
She used about 58.143 ft² of wrapping paper for each gift.
8 0
3 years ago
Read 2 more answers
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