Answer:
d. Perpendicular line through a point on a line
Step-by-step explanation:
We presume you're looking for a description of line HG.
The construction makes points H and G equidistant from points D and B, and it puts point C on the line HG. This makes HG perpendicular to AB, and it makes HG contain point C. Thus we have a perpendicular through a point on a line.
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Nothing about this construction creates an equilateral triangle or hexagon. The perpendicular is through points H and G, which are off the line AB, but we did not start with those. A perpendicular through an off-line point is constructed differently.
Alright, so let's make the length x and the width y. 2y=x, and xy=area. 2x+2y=perimeter. Plugging 2y=x into the perimeter equation, we get that 3x=perimeter=126, and x=126/3=42
Length=42ft, width=21ft
Answer:
22 (4th option)
Step-by-step explanation:
The side lengths are useless.
Pay attention to the angles.
<QRP=68 degrees.
Vertical angles make it so <SRT=68
180-90(right angle)-68=22 degrees
Let's calculate first, how many such numbers there are, where the same three digits are different form 0.
![\underbrace{1\cdot1\cdot1\cdot1}_{\text{XXX0}}\cdot\underbrace{9}_{\text{X=\{1,2,\ldots,9\}}}\cdot\underbrace{3}_{\text{XXX0,XX0X,X0XX}}=27](https://tex.z-dn.net/?f=%20%5Cunderbrace%7B1%5Ccdot1%5Ccdot1%5Ccdot1%7D_%7B%5Ctext%7BXXX0%7D%7D%5Ccdot%5Cunderbrace%7B9%7D_%7B%5Ctext%7BX%3D%5C%7B1%2C2%2C%5Cldots%2C9%5C%7D%7D%7D%5Ccdot%5Cunderbrace%7B3%7D_%7B%5Ctext%7BXXX0%2CXX0X%2CX0XX%7D%7D%3D27)
Now, the numbers where there are three 0's. There are only 9 of those
![1000,2000,\ldots,9000](https://tex.z-dn.net/?f=%201000%2C2000%2C%5Cldots%2C9000%20)
So, there are
such numbers.