Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
it is a :) hope this helped :)
Step-by-step explanation:
The answer to this is the exact same. It is 1325.
Answer:
![\boxed{\sf 200\pi}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20200%5Cpi%7D)
Step-by-step explanation:
We know that the volume of a cone:-
![\boxed{\sf \pi r^2\cfrac{h}{3}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%20%5Cpi%20r%5E2%5Ccfrac%7Bh%7D%7B3%7D%7D)
(r = 10) (h = 6)
![\sf \pi \times 10^2\times\cfrac{6}{3}](https://tex.z-dn.net/?f=%5Csf%20%5Cpi%20%5Ctimes%2010%5E2%5Ctimes%5Ccfrac%7B6%7D%7B3%7D)
<u>Divide numbers:-</u>
![\sf \cfrac{6}{3}=\boxed{2}](https://tex.z-dn.net/?f=%5Csf%20%5Ccfrac%7B6%7D%7B3%7D%3D%5Cboxed%7B2%7D)
![\sf 10^2\times \:2\pi](https://tex.z-dn.net/?f=%5Csf%2010%5E2%5Ctimes%20%5C%3A2%5Cpi)
![\sf 100\times \:2\pi](https://tex.z-dn.net/?f=%5Csf%20100%5Ctimes%20%5C%3A2%5Cpi)
<u>Multiply numbers:-</u>
![\boxed{\sf 200\pi}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20200%5Cpi%7D)
Therefore, your answer is 200π³
We could also multiply 200 by 3.14 which will give you 628 units³.
Answer:
16.5 ≈ x
Step-by-step explanation:
We have a right triangle where we know 1 side, 1 angle and we need to find another side. We can use trigonometric functions to find the missing side.
The tangent function definition is
tan α = opposite side/ adjacent side
In our problem
tan 70° = x/ 6, multiply both sides by 6 to isolate x
6 · tan 70° = x, use the calculator (make sure is set in degrees)
16.4848 ≈ x , round to the nearest tenths
16.5 ≈ x