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3 years ago

7

Would it be A or B?

1 answer:

Katyanochek1 [597]3 years ago

6 0

Try A
I think this is right
Hope this helps you :)

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Please help I’ll give brainliest

strojnjashka [21]

$\implies {\blue {\boxed {\boxed {\purple {\sf {D. \: {9}^{2} }}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

${9}^{5} \div {9}^{3}$

➼ $\: {9}^{5 - 3}$

➼ $\: {9}^{2}$

<h3><u>Note</u>:-</h3>

${a}^{m} \div {a}^{n} = {a}^{m - n}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

7 0

3 years ago

Given that secant theta = Negative StartFraction 37 Over 12 EndFraction, what is the value of cotangent theta, for StartFraction

Iteru [2.4K]

$cot\theta$ $=\frac{12}{35}$

Step-by-step explanation:

$sec\theta =\frac{37}{12}$

⇔ $\frac{1}{cos \theta} =\frac{37}{12}$

⇔ $cos \theta = \frac{12}{37}$

we know that

$sin \theta = \sqrt{1-cos^2\theta}$

$sin\theta =\sqrt{1-(\frac{12}{37})^2 }$

$sin\theta=\sqrt{\frac{1225}{1369} }$

$sin\theta = \frac{35}{37}$

Therefore $cot\theta =\frac{cos\theta}{sin\theta}$ $=\frac{\frac{12}{37} }{\frac{35}{37} }$ $=\frac{12}{35}$ , for $\frac{\pi}{2}$

8 0

3 years ago

Read 2 more answers

3x−2y=−2 6x−2y=10 solve by elimination

Anvisha [2.4K]

Answer:

x=4 y=7

Step-by-step explanation:

When multiplying 3x by -2, you get -6x. -6x and 6x cross out. You're left with -2y=-2 and -2y=10.

3 0

3 years ago

Helppp!!!! pleaseee!!!

melamori03 [73]

19% 0.23 1/5
1. 2. 3

4 0

3 years ago

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Solve for u<br> 5+4u=11<br> Simplify your answer as much as possible

r-ruslan [8.4K]

Answer:

u = 1.5

Step-by-step explanation:

5+4u=11

-5 -5

4u = 6

/4 /4

u=1.5

5 0

3 years ago