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Scrat [10]
3 years ago
14

A group of 47 children, with some adults, travelled by coach on a trip to a zoo.

Mathematics
2 answers:
brilliants [131]3 years ago
7 0

Answer:

5 adults

Step-by-step explanation:

plug in all numbers and calculate

Dvinal [7]3 years ago
4 0
Ok so the answer is 5 adults.
The total cost of the trip is $591 and the cost of hiring the coach was $118. So now what you did is that you subtract $591-$118=$473.
For entrance fee was $8.75 per each child and there was a total of 47 children. Then multiply 47x8.75 and you get $411.25. And then subtract 473 by 411.25 and which will be 61.75. And then the cost of each adult is $12.35. Then you divide 61.75 by 12.35.
Then when you divide it and the answer should be 5.
Which means that the amount of adults inside the group was 5.
Hope this helps!
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Leni [432]

Answer:

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Step-by-step explanation:

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3 years ago
Which is the simplified form of 7+5-12?
antiseptic1488 [7]

\green {\boxed{Answer}}

<h2>{r}^{ - 7}  +  {s}^{ - 12}</h2><h2>\frac{1}{ {r}^{7} }  +  \frac{1}{ {s}^{12} }</h2>

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4 0
3 years ago
Simplify the measurement using fractions. 10 inches is what part of a foot?
trasher [3.6K]
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7 0
3 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
Elden [556K]
We draw region ABC. Lines that connect y = 0 and y = x³ are vertical so:
(i) prependicular to the axis x - disc method;
(ii) parallel to the axis y - shell method;
(iii) parallel to the line x = 18 - shell method.

Limits of integration for x are easy x₁ = 0 and x₂ = 9.
Now, we have all information, so we could calculate volume.

(i)

V=\pi\cdot\int\limits_a^bf^2(x)\, dx\qquad\implies \qquad a=0\qquad b=9\qquad f(x)=x^3


V=\pi\cdot\int\limits_0^9(x^3)^2\, dx=\pi\cdot\int\limits_0^9x^6\, dx=\pi\cdot\left[\dfrac{x^7}{7}\right]_0^9=\pi\cdot\left(\dfrac{9^7}{7}-\dfrac{0^7}{7}\right)=\dfrac{9^7}{7}\pi=\\\\\\=\boxed{\dfrac{4782969}{7}\pi}

Answer B. or D.

(ii)

V=2\pi\cdot\int\limits_a^bx\cdot f(x)\, dx


V=2\pi\cdot\int\limits_0^{9}(x\cdot x^3)\, dx=2\pi\cdot\int\limits_0^{9}x^4\, dx=&#10;2\pi\cdot\left[\dfrac{x^5}{5}\right]_0^9=2\pi\cdot\left(\dfrac{9^5}{5}-\dfrac{0^5}{5}\right)=\\\\\\=2\pi\cdot\dfrac{9^5}{5}=\boxed{\dfrac{118098}{5}\pi}

So we know that the correct answer is D.

(iii)
Line x = h

V=2\pi\cdot\int\limits_a^b(h-x)\cdot f(x)\, dx\qquad\implies\qquad h=18


V=2\pi\cdot\int\limits_0^9\big((18-x)\cdot x^3\big)\, dx=2\pi\cdot\int\limits_0^9(18x^3-x^4)\, dx=\\\\\\=2\pi\cdot\left(\int\limits_0^918x^3\, dx-\int\limits_0^9x^4\, dx\right)=2\pi\cdot\left(18\int\limits_0^9x^3\, dx-\int\limits_0^9x^4\, dx\right)=\\\\\\=2\pi\cdot\left(18\left[\dfrac{x^4}{4}\right]_0^9-\left[\dfrac{x^5}{5}\right]_0^9\right)=2\pi\cdot\Biggl(18\biggl(\dfrac{9^4}{4}-\dfrac{0^4}{4}\biggr)-\biggl(\dfrac{9^5}{5}-\dfrac{0^5}{5}\biggr)\Biggr)=\\\\\\

=2\pi\cdot\left(18\cdot\dfrac{9^4}{4}-\dfrac{9^5}{5}\right)=2\pi\cdot\dfrac{177147}{10}=\boxed{\dfrac{177147\pi}{5}}

Answer D. just as before.

6 0
3 years ago
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