5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
Answer:
NM = 13
Step-by-step explanation:
pythagorean theorem: 
a or NO = 5
b or OM = 12
c or NM = ?
plug in what is known:
⇒ 
⇒ 
⇒ 169 = 
square root each side of the equation:
⇒ 
solve:
⇒ 13 = c
Answer:
Amount of gas that can be hold by Joe's tank = 16 gallons.
Step-by-step explanation:
Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.
So let's find change that happened after filling the gas.
Change = (5/8 full) - (1/4 full)
Change = (5/8 - 1/4) full
Change = (5/8 - 2/8) full
Change = (5 - 2)/8 full
Change = 3/8 full
So that means 3/8 full happens in 6 gallons
then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons
So the amount of gas that can be hold by Joe's tank = 16 gallons.
Answer:
A =First term of the pattern = 11
To find the first five terms we have to use the rule which is
Add 10 to first term and then subtract 5 from it.Which is equivalent to
= A +10 -5
1. Second Term = 11 + 10 -5
= 21 - 5
=16
→Third term = 16 +10-5
= 26 - 5
= 21
→Fourth term : 21 + 10 - 5
= 31 -5
= 26
→Fifth term : 26 +10 -5
= 36- 5
= 31
→Sixth term:
=31 + 10- 5
= 41 -5
= 36
So, the first five term apart from 11 is 16, 21,26,31,36 which is an Airthmetic progression.
