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svetlana [45]
3 years ago
12

The type of part being manufactured today should be 1.27 inches wide, with a tolerance of 0.04 inches. If a part does not meet t

he size requirement, it must be rejected. You have 4 parts to inspect. They have the following widths. How many must be rejected?
1.275 inches, 1.300 inches, 1.266 inches, 1.255 inches
Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

The range of widths is {1.23,1.31} so none will be rejected, answer A.

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(4,?) is on the line 8x - 3y = -10. Find the other half o the coordinate
Charra [1.4K]
(4, ?) is on 8x - 3y = -10

The ? is the missing y coordinate.  (4, y) satisfies 8x - 3y = -10

8x - 3y = -10.      From point (4, y),  we would replace x = 4 in the equation below. y remains the unknown.

8*4 - 3y = -10

32 - 3y = -10

-3y = -10 - 32

-3y = - 42

y = -42/-3

y = 14

So the coordinate is (4, 14)
6 0
3 years ago
On August 20, 1989, in Cologne, West Germany, Said Aouita of Morocco also established a world record when he ran the 3000. m run
zalisa [80]

Answer:

Average speed of Aouita = 6.68 meter per second.

Step-by-step explanation:

To create a world record Aouita ran a distance = 3000 m

He took the time to cover this distance = 7 minutes 29.45 seconds

                                                                 = (7×60) + 29.45 seconds

                                                                 = 449.45 seconds

Since, formula for the average speed is given by,

Average speed = \frac{\text{Total distance covered}}{\text{Total time taken}}

Therefor, average speed of Aouita = \frac{3000}{449.45}

                                                          = 6.675

                                                          ≈ 6.68 meter per second

Average speed of Aouita was 6.68 meter per second.

8 0
3 years ago
X/45=7/9 solve the proportions
Iteru [2.4K]
The answer is 35 because u need to multiply 7 by 5 because they multiply 9 by 5.
7 0
4 years ago
Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me​
Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

<h3><u>Part (a)</u></h3>

\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}

<h3><u>Part (b)</u></h3>

\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}

<h3><u>Part (c)</u></h3>

\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}

\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}

<h3><u>Part (d)</u></h3>

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0

7 0
2 years ago
Solve for x, 12y+6=6(y+1)
Vanyuwa [196]

For this case we must solve the following equation:

12y + 6 = 6 (y + 1)

We apply distributive property on the right side of the equation:

12y + 6 = 6y + 6

We subtract 6y on both sides of the equation:

12y-6y + 6 = 6\\6y + 6 = 6

We subtract 6 from both sides of the equation:

6y = 6-6\\6y = 0

Dividing by 6 on both sides of the equation:

y = 0

So, the result is y = 0

Answer:

y = 0

4 0
4 years ago
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