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mariarad [96]
3 years ago
10

Hhelp...........pls.................

Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

Answer:

Not really sure but heree

Step_by_step

True

andre [41]3 years ago
7 0

Answer:

True

Step-by-step explanation:

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Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.
Margaret [11]
◆ INEQUALITIES ◆

given \: expression \:  \:  -  \\  \\ 12s - 20 \leqslant 50 - 3s - 25 \\  \\ 12s - 20 \leqslant 25 - 3s \\  \\ adding \: 20 \: both \: sides \:  \: , \:  \\ we \: get \:  -  \\  \\ 12 s  \leqslant 45 - 3s \\  \\ 12s + 3s \leqslant 45 \\  \\ 15s \leqslant 45 \\ s \leqslant  \frac{45}{15}  \\  \\ \\    s \leqslant 3 \:  \:  \:  \:  \:  \: ans.
8 0
3 years ago
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
Point C is twice as close to point B as it is to point A. If point A is at -30 and point B is at 30, what are two possible value
arsen [322]

different between A and B

=30-(-30)

=60

position of C from A or B

=(60÷3)×2

=40

possible value of c

=-30+40

=10

possible value of c

=30-40

=-10

8 0
3 years ago
Read 2 more answers
Select all of the equations that are equivalent to<br>2-5y=-7​
insens350 [35]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Henry has a fenced yard in the shape of a rectangle with a perimeter that measures 242 feet. If the width of the yard measures 5
neonofarm [45]

Answer: Length = 70 feet

Concept:

Here, we need to know how to find the perimeter of a rectangle.

Perimeter (rectangle) = 2 (l + w)

l = length

w = width

Solve:

<u>Given information</u>

l = l

w = 51 feet

P = 242 feet

<u>Given expression</u>

P = 2 (l + w)

<u>Substitute values into the expression</u>

242 = 2 (l + 51)

<u>Divide 2 on both sides</u>

242 / 2 = 2 (l + 51) / 2

121 = l + 51

<u>Subtract 51 on both sides</u>

121 - 51 = l + 51 - 51

\boxed{l=70}

Hope this helps!! :)

Please let me know if you have any questions

4 0
2 years ago
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