Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
different between A and B
=30-(-30)
=60
position of C from A or B
=(60÷3)×2
=40
possible value of c
=-30+40
=10
possible value of c
=30-40
=-10
Answer:
c
Step-by-step explanation:
Answer: Length = 70 feet
Concept:
Here, we need to know how to find the perimeter of a rectangle.
Perimeter (rectangle) = 2 (l + w)
l = length
w = width
Solve:
<u>Given information</u>
l = l
w = 51 feet
P = 242 feet
<u>Given expression</u>
P = 2 (l + w)
<u>Substitute values into the expression</u>
242 = 2 (l + 51)
<u>Divide 2 on both sides</u>
242 / 2 = 2 (l + 51) / 2
121 = l + 51
<u>Subtract 51 on both sides</u>
121 - 51 = l + 51 - 51

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