Answer:
75%
Step-by-step explanation:
Answer:
Step-by-step explanation:
The slope of the line in question is the same as the slope of the line parallel to it. Using y = mx + b, where m is the slope, we find the slope of our line is -3.
Using the pt-slope form, y - y1 = m( x - x1), we get y - (-1) = -3( x - 2) or y + 1 = -3x + 6. Which leads us to y = -3x + 5. QED
Domain is x values... Y is y values
The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)

Substitute eqn 1 in above equation

Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
Answer:
14 month
Step-by-step explanation:
Lets create equations for these two gyms. I believe this is an algebra 1 problem.
Community Gym: y=70x+50
Workout Gym: y=60x+190
Because both gyms are equal to y, we can set them together and solve for x.
70x+50=60x+190
10x=140
x=14
You can find the cost by plugging in 14 into both of the equations. You get a cost of $1030 after 14 months
Therefore, after 14 months you will have paid the same amount for both gyms.