Two balls are drawn in succession out of a box containing 2 red and 5 white balls. Find the probability that at least one ball w
as red , given that the first ball was:
(A) replaced before the second draw.
(B) not replaced before the second draw.
1 answer:
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➷ A) (2/7 x 2/7) + (2/7 x 5/7) + (5/7 x 2/7) =
4/49 + 10/49 + 10/49 = 24/49 <== this is the answer
B) (2/7 x 1/6) + (2/7 x 5/6) + (5/7 x 2/6) -
2/42 + 10/42 + 10/42 = 22/42 <== this is the answer
The second answer could be simplified to 11/21 (only write this answer if it wants the simplified version, otherwise write the one above)
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Your answer is -8, tell me if you need help trying to figure these out.
Greeting!
15x² = x + 2
15x² - x -2= 0
Factor left side
(5x-2)(3x+1)=0
Set factors equal to 0
5x - 2 = 0 or 3x + 1 -0
x = 2/5 or x= -1/3
I hope that helps!
Brainlest answer :)
Here is how to work it with long division.
Answer:
0.16
Step-by-step explanation:
if the number in the thousandths is 5 or over you round it up.
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