6( 9 +5 - 2) = * help plz
1 answer:
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See the attached picture to better understand the problem
we know that
in rectangle ABCD
AB=CD
and
AD=BC
therefore
the triangle ACD and triangle ABC are congruent
so
BD=AC
BD=8 units
the answer part a) is
BD= 8 units
Part b) Find angle CBD
we know that
∠ABD+∠CBD=90°---------> by complementary angles
so
∠CBD=90-∠ABD-----> 90-67----> 23°
∠CBD=23°
the answer Part b) is
∠CBD=23 degrees
we know that
in rectangle ABCD
AB=CD
and
AD=BC
therefore
the triangle ACD and triangle ABC are congruent
so
BD=AC
BD=8 units
the answer part a) is
BD= 8 units
Part b) Find angle CBD
we know that
∠ABD+∠CBD=90°---------> by complementary angles
so
∠CBD=90-∠ABD-----> 90-67----> 23°
∠CBD=23°
the answer Part b) is
∠CBD=23 degrees
Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)
One of them is real and the other two are complex conjugate roots
Since the real root is 4, then
x = 4
Since the complex root is (1 - i), then
The other root will be the conjugate of it (1 + i)
x = (1 - i)
x = (1 + i)
To find f(x) we will multiply the three factors of it
We can get the factors from the zeroes
Subtract 4 from both sides
The first factor is (x - 4)
The second factor is (x - 1 + i)
The third factor is (x - 1 - i)
We will multiply them to find f(x)
Multiply it by (x - 4)
The answer is