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Gekata [30.6K]
3 years ago
11

The san paulo community swimming pool can be filled in 12 hr if water enters through a pipe alone or in 30 hr if water enters th

rough a hose alone. if water is entering through both the pipe and the hose, how long will it take to fill the pool?
Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Alright, lets gets started.

If water enters through a pipe alone, swimming pool can be filled in 12 hr.

Or say, in 12 hrs, swimming pool can be filled with help of pipe.

It means in 1 hr, the part of swimming pool filled = \frac{1}{12} (For pipe only)

Similarly, with hose only, , in 1 hr, the part of swimming pool filled = \frac{1}{30}

So, water is coming from both, pipe and hose , then in 1 hr, the part of pool filled will be = \frac{1}{12}  + \frac{1}{30}

Suppose in x hrs, with both supplies, pipe and hose, pool is filled.

Means

\frac{1}{12}  + \frac{1}{30}  = \frac{1}{x}

making common denominator

\frac{30}{360}   + \frac{12}{360}  = \frac{1}{x}

\frac{30 + 12}{360} = \frac{1}{x}

\frac{42}{360}  = \frac{1}{x}

Flipping

\frac{360}{42}  = x

x = \frac{60}{7}

Means 8.57 hrs : Answer

Hope it will help :)

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Cesar turned in his third research report, his teacher said that he had completed 20%of the reports for the school year, how man
AleksAgata [21]

Answer:

Cesar will be doing  15 research reports during the school year.

Step-by-step explanation:

Given:

Number of research report completed = 3

Percentage of the report completed for school year = 20%

We need to find total number of research report completed during school year.

Solution:

Let the total number of research report completed during school year be 'x'.

Now we can say that;

Number of research report completed is equal to Percentage of the report completed for school year multiplied by total number of research report completed during school year and then divided by 100.

framing in equation form we get;

3=\frac{20}{100}\times x\\\\3=0.2x

Dividing both side by 0.2 we get;

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Hence Cesar will be doing  15 research reports during the school year.

6 0
3 years ago
At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel
Alexeev081 [22]
Use Law of Cooling:
T(t) = (T_0 - T_A)e^{-kt} +T_A
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
42 = (80-20)e^{-3k} +20 \\  \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\  \\ k = -\frac{1}{3} ln (\frac{11}{30})

Substituting k back into cooling equation gives:
T(t) = 60(\frac{11}{30})^{t/3} + 20

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\  \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80
Solve for x:
x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80
Sub back into original cooling equation, x = T(t)
-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20
Solve for t:
60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3}  = 60 \\  \\  (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\  \\  \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\  \\ \\  t = 4.959

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
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3 years ago
En un pastel que se quiere repartir a 5 personas, se logran generar 8 piezas al cortarlo, cual de las siguientes expresiones ref
Anon25 [30]

Answer:

La respuesta es 1/5.

Step-by-step explanation:

porque el 1 pastel se divide en 5 personas.

Espero que esto ayude.

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PLS HELP<br>Worth 20 Points<br>Easy <br>I will give brainilest​
erma4kov [3.2K]

Answer:

x-axis

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=3x%20-%202y%20%3D%2043x%20%2B%202y%20%3D%208" id="TexFormula1" title="3x - 2y = 43x + 2y = 8"
den301095 [7]

3x - 2y = 8 +

===》 46x = 16

43x + 2y = 8

x = 16/46

x = 8/23

______________________________

3x - 2y = 8

3(8/23) - 2y = 8

24/23 - 2y = 8

2y = 24/23 - 8

y = 12/23 - 4

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