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Gekata [30.6K]
3 years ago
11

The san paulo community swimming pool can be filled in 12 hr if water enters through a pipe alone or in 30 hr if water enters th

rough a hose alone. if water is entering through both the pipe and the hose, how long will it take to fill the pool?
Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Alright, lets gets started.

If water enters through a pipe alone, swimming pool can be filled in 12 hr.

Or say, in 12 hrs, swimming pool can be filled with help of pipe.

It means in 1 hr, the part of swimming pool filled = \frac{1}{12} (For pipe only)

Similarly, with hose only, , in 1 hr, the part of swimming pool filled = \frac{1}{30}

So, water is coming from both, pipe and hose , then in 1 hr, the part of pool filled will be = \frac{1}{12}  + \frac{1}{30}

Suppose in x hrs, with both supplies, pipe and hose, pool is filled.

Means

\frac{1}{12}  + \frac{1}{30}  = \frac{1}{x}

making common denominator

\frac{30}{360}   + \frac{12}{360}  = \frac{1}{x}

\frac{30 + 12}{360} = \frac{1}{x}

\frac{42}{360}  = \frac{1}{x}

Flipping

\frac{360}{42}  = x

x = \frac{60}{7}

Means 8.57 hrs : Answer

Hope it will help :)

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A rectangular area is to be enclosed by a wall on one side and fencing on the other three sides. If 18 meters of fencing are use
Rashid [163]

Answer:

A = L W= 9*\frac{9}{2}=\frac{81}{2} m^2

Step-by-step explanation:

For this case we assume that the total perimeter is 18 ft, we have a wall and the two sides perpendicular to the wall measure x units each one so then the side above measure P-2x= 18-2x.

And we are interested about the maximum area.

For this case since we have a recatangular area we know that the area is given by:

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Where L is the length and W the width, if we replace from the values on the figure we got:

A(x)= x *(18-2x) = 18x -2x^2

And as we can see we have a quadratic function for the area, in order to maximize this function we can use derivates.

If we find the first derivate respect to x we got:

\frac{dA}{dx} = 18-4x=0

We set this equal to 0 in order to find the critical points and for this case we got:

18-4x=0

And if we solve for x we got:

x=\frac{18}{4}=\frac{9}{2} m

We can calculate the second derivate for A(x) and we got:

\frac{d^2 A}{dx^2}= -4

And since the second derivate is negative then the value for x would represent a maximum.

Then since we have the value for x we can solve for the other side like this:

L= 18-2x = 18-2 \frac{9}{2}= 18-9 =9m

And then since we have the two values we can find the maximum area like this:

A = L W= 9*\frac{9}{2}=\frac{81}{2} m^2

8 0
3 years ago
What is the perimeter of triangle PQR? Show your work.
xxMikexx [17]

Answer:

The perimeter of triangle PQR is 17 ft

Step-by-step explanation:

Consider the triangles PQR and STU

1. PQ ≅ ST = 4 ft (Given)

2. ∠PQR ≅ ∠STU  (Given)

3. QR ≅ TU = 6 ft (Given)

Therefore, the two triangles are congruent by SAS postulate.

Now, from CPCTE, PR = SU. Therefore,

3y-2=y+4\\3y-y=4+2\\2y=6\\y=\frac{6}{2}=3

Now, side PR is given by plugging in 3 for 'y'.

PR = 3(3) - 2 = 9 - 2 = 7 ft

Now, perimeter of a triangle PQR is the sum of all of its sides.

Therefore, Perimeter = PQ + QR + PR

                                   = (4 + 6 + 7) ft

                                   = 17 ft

Hence, the perimeter of triangle PQR is 17 ft.

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Solve for x.<br> 3x/6 + 2 = 8
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Answer:

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3x/6 + 2-2 = 8-2

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Multiply each side by 6/3

6/3 * 3/6 x = 6 *6/3

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6 0
3 years ago
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Suppose the time to complete a 200-meter backstroke swim for female competitive swimmers is normally distributed with a mean μ =
Natali [406]
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(128 - 141) / 7 = -1.86

Now, use a standard normal distribution table to determine the percent below a z-score of -1.86. That value is 0.0314 or 3.14%.
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