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Nataly_w [17]
3 years ago
11

1. A piece of wire that is 28 inches long is cut into two pieces, each of which is then bent into the shape of a square. The lar

ger square has side lengths that are three inches longer than the smaller square.
(a) If x is the side length of the smaller square and y is the side length of the larger square, write a system of equations that models this scenario.
(b) Solve the system of equations and determine the lengths of the two pieces of wire.
Mathematics
1 answer:
sesenic [268]3 years ago
5 0

Answer:

a)x+y=7 and y-x=3

b)x=2 and y=5

Step-by-step explanation:

The total of the two perimeters must equal 28. That is:

4x+4y=28

x+y=7 <em>(simplified)</em>

The larger side length is 3 inches longer than the smaller side length. That is:

y=x+3

Sub 'x+3' in for y:

x+(x+3)=7

x+x=7-3

2x=4

x=2

y=x+3

=2+3

=5

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Length = 120+20
width = 120

answer:
length=140
width=120

check:
140x2=280
120x2=240
280+240=520
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4 0
3 years ago
Please help I don't understand!
levacccp [35]

Answer:

9

Step-by-step explanation:

Take the sides in proportion.

⇒ \frac{AE}{AD} =\frac{AB}{AC}

⇒ \frac{12}{12+8} =\frac{x}{15}

⇒ \frac{12}{20} =\frac{x}{15}

⇒ \frac{3}{5} =\frac{x}{15}

⇒ 3 = \frac{x}{3}

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3 0
2 years ago
A ski gondola carries skiers to the top of a mountain. assume that weights of skiers are normally distributed with a mean of 199
Allushta [10]
A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb

</span>B)  First, find the z-score:
z = (value - mean) / stdev
   = (150 - 199) / 41
   = -1.20

We need to find P(z > -1.20) = 1 - P(z < -1.20)

Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849

Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>

C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb

Let's repeat the steps of point B)

z = (187.5 - 199) / 41
   = -0.29

P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141

</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%

D) The mean weight of skiers is 199lb, therefore:
number</span> of passengers = <span>load limit ÷ <span>mean weight of passengers
                                     = 3750 </span></span><span>÷ 199
                                     = 18.8
The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
4 0
3 years ago
Hi I am new to this!! Can someone please help me
Ivanshal [37]

Answer:Pretty sure it’s c

Step-by-step explanation:

5 0
3 years ago
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