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NNADVOKAT [17]
3 years ago
6

What is the median of the data set?

Mathematics
1 answer:
lara [203]3 years ago
6 0
<span>42 55 27 31 17 24 65 47 39 18

median is the middle term in an ascending arranged term

17  18  24  27  31  39  42  47  55  65    

so, median will be mean of 31 and 39  = 35

hope it helped


</span>
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ten years ago, the ratio of two brothers was 1:4. fourteen years from now, the ratio will be 4:7. What is the ratio of their pre
andrey2020 [161]

The ratio of their age is 3:7.

Step-by-step explanation:

Given,

10 years ago, the ratio of two brothers was 1:4

After 14 years the ratio will be 4:7

To find the ratio of their present age.

Let,

10 years age their age was x and 4x

So, now their age is (x+10) and (4x+10)

14 years from now their age will be (x+10+14) and (4x+10+14)

That is x+24 and 4x+24

According to the problem,

x+24 : 4x+24 = 4:7

or, \frac{x+24}{4x+24} = \frac{4}{7}

or, 7(x+24) = 4(4x+24)

or, 7x+168 = 16x+ 96

or, 16x-7x = 168-96

or, 9x = 72

or, x = 8

Hence,

Their present age is (8+10) and (4×8+10) = 18 and 42

Hence,

The ratio of their age is 18:42 = 3:7

3 0
3 years ago
Help Help Help!!! :)<br> solve the system of equations y=2x^2-3 y=3x-1
stellarik [79]
Solution:  
y = 2x^2 - 3 ---- equation 1
 y = 3x - 1 ------equation 2 
 Then we get, 
 2x^2 - 3 = 3x - 1 
 Now, simplifying the equation, we get 
 2x^2 - 3x - 3 + 1 = 0
 2x^2 - 3x - 2 = 0 
 After factoring the equation, we get
 (2x+1)(x-2) = 0 
 So, this means
 (2x+1) = 0 and (x-2) = 0 
 From this, we get 
 x = -1/2 and x = 2 
 Putting values of x = -1/2 in equation 2 
 y = 3(-1/2) - 1
 y = -2.5 
 Now, putting value of x = 2 in equation 2 
 y = 3(2) -1
 y = 5
4 0
4 years ago
4. In the diagram below, ZABD = (4x + 3)º and DBC = (7x-6)º.
blsea [12.9K]

Answer:

Step-by-step explanation:

a) ∠ABD + ∠DBC = 90°

4x - 3 + 7x - 6 = 90

4x + 7x - 3 - 6 = 90

       11x -  9     = 90

              11x    = 90 + 9

              11x    = 99

                   x = 99/11

x = 9

∠ABD = 4*9 - 3 = 36 - 3 = 33

4 0
2 years ago
Can anyone help me on D?
Sophie [7]

Answer: make it bigger~

Step-by-step explanation:

7 0
2 years ago
The energy information administration reported that the mean retail price per gallon of regular grade gasoline was $3.43. Suppos
Morgarella [4.7K]

Answer:

68.26% of regular grade gasoline sold between $3.33 and $3.53 per gallon

81.85% of regular grade gasoline sold between $3.33 and $3.63 per gallon

2.28% of regular grade gasoline sold for more than $3.63 per gallon

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3.43, \sigma = 0.1

What percentage of regular grade gasoline sold between $3.33 and $3.53 per gallon?

This is the pvalue of Z when X = 3.53 subtracted by the pvalue of Z when X = 3.33. So

X = 3.53

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.53 - 3.43}{0.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 3.33

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.33 - 3.43}{0.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% of regular grade gasoline sold between $3.33 and $3.53 per gallon

What percentage of regular grade gasoline sold between $3.33 and $3.63 per gallon?

This is the pvalue of Z when X = 3.53 subtracted by the pvalue of Z when X = 3.33. So

X = 3.63

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.63 - 3.43}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 3.33

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.33 - 3.43}{0.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.9772 - 0.1587 = 0.8185

81.85% of regular grade gasoline sold between $3.33 and $3.63 per gallon

What percentage of regular grade gasoline sold for more than $3.63 per gallon?

This is 1 subtracted by the pvalue of Z when X = 3.63. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.63 - 3.43}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of regular grade gasoline sold for more than $3.63 per gallon

3 0
3 years ago
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