<span>Let the distance of the point be P. From the question, the distance, P, is square root of the sum of the coordinates (x, y); so we have (X^2, Y^2) From the origin we have (0, 0) From elementary mathematics, distance of a point is . âš(X2 -X1)^2 - (Y2 - Y1)^2
So basically this is just the difference of the squares at varying points of X and Y.
At the origin, X1 = 0 and Y1 = 0 and so our equation reduces to âš(X2-0)^2 + (Y2 -0)^2. This becomes P =âšX^2 + Y^2</span>
No, because x/2 divides x by two, while -2x multiplies x by -2.
Look at the first element of each point:
{4, 1, 0, 1} (do not write 4 twice, even tho' 4 shows up twice).
This is NOT a function, altho' it still is a relationship. Why? Because 4 shows up as an input twice. In the case of a function, no input shows up more than once.
Answer:
21
Step-by-step explanation:
7x3=21
21/3=7
you just have to use inverse operations
(: hope this helps
You can recognize the limit as a derivative. Recall that
and more to the point,
We have
so the answer is B.
We don't actually have to invoke the definition of the derivative. Instead we can just use the definition of
:
which you can see also approaches 4.