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Oduvanchick [21]
3 years ago
5

What is 30% of 70? A:9 B:12 C:19 D:21​

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

21

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Help me solve this please -22-x=5+6x+9
ollegr [7]

Answer: x = -5  1/7

Step-by-step explanation:

-22 - x = 5 + 6x + 9

First, combine the like terms 5 and 9

5 + 9 = 14

-22 - x = 14 + 6x

Add x to each side

-22 = 14 + 7x

Subtract 14 from each side

-36 = 7x

Divide each side by 7

x = -5 1/7 (Yes, a fraction.)

8 0
3 years ago
I need to get 2 answered please help it’s with mean, median and mode
Marat540 [252]
They are all averages

mean=average 4+6=10, 10 divded by 2= 5, the mean is 5

median= middle number, 5 6 7, 6 is the median
mode= most repeated number, so 4,4,4,4,4,4,4,5.5,6       4 is the mode
7 0
3 years ago
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
Three candy bars are being shared equally between four friends.
astraxan [27]

Answer:

\frac{3}{4}

3 0
3 years ago
The ratio of an object's weight on Earth to its weight on Mars is 5 to 2. How much would a man, who weighs 145 pounds on Earth,
butalik [34]
To answer this youd have to set up a proportion. 5/2 is the ratio of weight on earth and mars respectively. The other side has to have the same ratio where 125lbs is the weight on earth and x is the weight on mars. The equation would look like 5/2=125/x. Youd have to cross multiply, and would get (125)(2)=5x. Solve for x to find the weight on mars
6 0
4 years ago
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