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e-lub [12.9K]
3 years ago
15

An electronic games manufacturer producing a new product estimates the annual sales to be 8000 units. Each year 2% of the units

that have been sold will become inoperative. So, 8000 units will be in use after 1 year, [8000 0.98(8000)] units will be in use after 2 years, and so on. How many units will be in use after n years
Mathematics
1 answer:
Ugo [173]3 years ago
5 0
400 or 4/80 would be after n years
You might be interested in
If y-x=4 and x is three times the value of y, what is the value of x + y?
Eduardwww [97]

Answer:

E = 8

Step-by-step explanation:

y - x = 4

y - (3y) = 4

y - 3y = 4

2y = 4

y = 4/2

y = 2

x = 3y

x = 3×2

x = 6

x + y = 2+6

x+y = 8

6 0
2 years ago
Can someone please help me with this!!
miv72 [106K]
Hello there! Given the expression, we can solve through a series of steps:

1. Simplify

-5 + 7 • 1

2. Multiply (according to order of operations)

7 • 1 = 7

3. Add

-5 + 7 = 2

Your final answer is 2. Hope this helps!
8 0
1 year ago
PLZPLZ PLZ PLZ PLZ PLZ HELP ME I AM CONFUSED ND DONT KNOW WHAT TO DO!!
Dominik [7]
The answer to your question is 2
7 0
3 years ago
Read 2 more answers
Write the equation for:
svetlana [45]

Answer:

1. -16-(-11)=5

2.48 divided by -8 is 12

3.13/5=2

4.81-11=7

5.3*2=35

6 35*2=5

Step-by-step explanation:

6 0
4 years ago
Kind of confused on this question, please help
Wittaler [7]

Answer:

4th option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{3}{5} x - 6 ← is in slope- intercept form

with slope m = \frac{3}{5}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{3}{5} } = - \frac{5}{3}

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - \frac{5}{3} and (a, b ) = (- 2, 5 ) , then

y - 5 = - \frac{5}{3} (x - (- 2) ) , that is

y - 5 = - \frac{5}{3} (x + 2)

8 0
3 years ago
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