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Oliga [24]
3 years ago
9

I need help asap worth 100pts

Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Answer:

<u>Part (a)</u>

It depends how your calculator calculates quadratic regressions.

For my calculator:

  • Go to Statistics menu
  • Select quadratic regression: y=a+bx+cx²
  • Input the x and y values from the given table
  • Go to options and select regression calc

a = 1.177142857 = 1.18 (nearest hundredth)

b = 42.22257143 = 42.22 (nearest hundredth)

c = -12.87142857 = -12.87 (nearest hundredth)

⇒ y = 1.18 + 42.22x - 12.87x²

Therefore, the quadratic regression equation in standard form is:

y = -12.87x^2+ 42.22x + 1.18

<u>Part (b)</u>

To estimate the height of the rocket after 5 seconds, input x = 5 into the regression equation:

\implies  -12.87(5)^2+ 42.22(5) + 1.18=-109.47

As this gives us a negative value, this means that the rocket would have come back to the ground before 5 s.  Therefore, the height of the rocket at 5 s will be 0 ft.

(see attached graph → the rocket will hit the ground at approx 3.3 s)

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<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches

The values of the side lengths when x = 2 are

(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch

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Thus perimeter of the quadrilateral is 129 inches

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