Please help ASAP!! it’s for geometry
1 answer:
You might be interested in
Answer:
y-7 = -2 (x-4)
Step-by-step explanation:
Point Slope Form:
, where m is the slope of the line
They tell you that the line has a slope of -2, so that will go in the first yellow box. They also tell you that the line passes through the point (4, 7), so those are the values for x1 and y1. They've already filled in y1 with 7, so x1 (which is 4) will go in the second yellow box
y-7 = -2 (x-4)
Answer:
The answer is (0 , 2) , (-6 , 2) , (-4 , 5)
The 3rd picture
Step-by-step explanation:
* Lets talk about the reflection across x-axis and then the
rotation clockwise around the origin
- If the point is (x , y), and rotate it across the x- axis, that
means we will change the position of the point from up to
down or from down to up the x-axis, so we will change the
sign of the y-coordinate, then the image is (x , -y)
* From the graph the vertices of the triangle are
(-2 , 0) , (-2 , 6) , (-5 , 4)
* After the reflection across x-axis their images will be
(-2 , 0) , (-2 , -6) , (-5 , -4)
* The rotation around the origin with 90° clockwise means
we will turn each point by 90° from up and right to right and
down
- That means we switch x-coordinate and y-coordinate and
change the sign of x-coordinate, then the image is (y , -x)
* Lets Rotate the vertices of the triangle (-2 , 0) , (-2 , -6) , (-5 , -4)
* After rotation 90° clockwise around the origin their images will be
- (0 , 2) , (-6 , 2) , (-4 , 5)
* Look to all answer we will find the third picture is the right answer
- The right picture is attached
Answer:
12.92%
Step-by-step explanation:
Mean of the scores= u = 500
Standard deviation = = 10.6
We have to find what proportion of students scored more than 512 marks.
The distribution of scores in a test generally follows the Normal distribution. So we can assume that the distribution of MCAT scores is normally distributed about the mean.
Since, the distribution is normal, we can use the concept of z scores to find the proportion of students who scored above 512.
The formula for z scores is:
So, z score for x = 512 will be:
Thus,
P(X > 512) is equivalent to P(z > 1.13)
So, the test scores of 512 is equivalent to a z score of 1.13. Using the z table we have to find the proportion of z scores being greater than 1.13, which comes out to be 0.1292
Since,
P(X > 512) = P(z > 1.13)
We can conclude that, the proportion of students taking the MCAT who had a score over 512 is 0.1292 or 12.92%