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3 years ago

CAN SOMEONE PLEASE HELP ME!! THANK YOU

Mathematics

2 answers:

Mila [183]3 years ago

7 0

Answer:

Step-by-step explanation:

I'm pretty sure it's C

iren [92.7K]3 years ago

5 0

Answer:

not sure but b or c because it says less than

Step-by-step explanation:

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Koji is installing a rectangular window in an office building. The window is 823 ft wide and 534 ft high. The formula for the ar

IrinaK [193]

A = b * h
b = 8 2/3
h = 5 3/4

A = 8 2/3 * 5 3/4.....turn to improper fractions
A = 26/3 * 23/4
A = 598/12
A = 49 5/6 ft^2 <====

4 0

3 years ago

Give examples of two substances that look similar, but have different properties.

gogolik [260]

Answer:

Water and alcohol

Step-by-step explanation:

They are both a clear liquid. However, their properties are very different. Here are a few of the things that set them apart.

their smell
their PH
their density

8 0

3 years ago

Please help! ill give brainliest

anastassius [24]

Answer:

y=-6

Step-by-step explanation:

1. plug in the values, it will be y=4/3(-6) + 2

2. simplify

y=-24/3 + 2

y=-8+2

y=-6

I hope this helped, and if it did, please mark this as brainliest! thanks

4 0

3 years ago

Plz will gave a brain who ever answer this will get a brain

inessss [21]

Energy in the form of HEAT

8 0

3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0

3 years ago